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3 years ago

For what value of x is the equation 2^2x+7=2^15

Mathematics

1 answer:

ss7ja [257]3 years ago

4 0

Answer:

X=3/4

Step-by-step explanation:

2^2x+7=2^15

4x+7=2^1 X 5

4x+7=2 X 5

4x+7=10

4x+7-7=10-7

4x=3

4X/4 = 3/4

X=3/4

I hope this helps!

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When Θ = 5 pi over 3, what are the reference angle and the sign values for sine, cosine, and tangent?

Sonbull [250]

Answer:

the reference angle is given by $\frac{\pi}{3}$

sine = negative

cosine = positive

tangent = negative

Step-by-step explanation:

We have been given the angle $\theta=\frac{5\pi}{3}$

The angle lies in Quadrant IV. Hence, in order to find the reference angle, we can subtract this angle with $2\pi$

Therefore, the reference angle is given by

$2\pi - \frac{5\pi}{3} \\\\=\frac{\pi}{3}$

In Quadrant IV, cosine and secant functions are positive and rest trigonometric functions are negative.

Thus, we have

sine = negative

cosine = positive

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4 years ago

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goblinko [34]

Answer:

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Step-by-step explanation:

In the picture attached the histogram is shown. We can see that data is skewed to the right, so we have to use the five-number summary. The range of the data is 39 - 1 = 38 (subtraction of the maximum value to the minimum value); the median is (15 + 17)/2 = 16 (if you order the values, 15 and 17 are in the middle); quartile 1 is 9.25 and quartile 3 is 25.5 (see diagram of box and whisker attached), then half of the data are between those values.

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3 years ago

One of the diagonals of a rhombus of perimeter 120m is 36m. Find its area and the length of the other diagonal. pls answer fastt

mash [69]

Answer: $864\ m^2,\ 24\ m$

Step-by-step explanation:

Given

Perimeter of the rhombus is $120\ m$

Length of one of the diagonal is $d_1=36\ m$

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Area of the rhombus with side and one diagonal is

$\Rightarrow \text{Area=}\dfrac{1}{2}d\sqrt{4a^2-d^2}$

Insert the values

$\Rightarrow \text{Area=}\dfrac{1}{2}\times 36\times \sqrt{4\cdot 30^2-36^2}\\\\\Rightarrow \text{Area= }18\sqrt{3600-1296}\\\Rightarrow \text{Area= }18\times 48\\\Rightarrow \text{Area= }864\ m^2$

Area with two diagonals length can be given by

$\Rightarrow \text{Area =}0.5\times d_1\times d_2 \\\text{Insert the values}\\\Rightarrow 864=36\times d_2\\\Rightarrow d_2=24\ m$

Thus, the area of the rhombus is $864\ m^2$ and the length of the other diagonal is $24\ m$

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3 years ago

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Keith_Richards [23]

Explanation:
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3 years ago