<span>[ (3x6) ] + (5x2) ] ÷ 7
= (18 + 10)/7
= 28/7
= 4</span>
Answer:
18225
Use the formula: .
A = final amount
P = initial amount invested
r = annual interest rate
t = time (in years)
Insert all values in appropriate places.
Simplify.
A=16200(1+(0.025)(6))
Alright! When you have a constant to a power times another constant to a power (ex. [x^3 times x^3] ) you simply add the powers and keep the base [x^6]. When you have a power to a power (ex. [(12^3)^3] ) you multiply the powers and keep the base [12^9]. When you have a constant to a power divided by a constant to a power (ex. [ x^2 divided by x^5] ) you subtract the powers and keep the base. It's hard to see the questions, so I'll leave this here for you to use as a guide.
At time t = 1 hr... fee is initial ($12)+ ($8) = 20<span><span>ribhu </span> 10 months ago</span>and so on... the intercept would be initial fee... which is $12 charged at t=0 hr
thats the best i can do
