Answer:
7.33
Step-by-step explanation:
Answer: Provided.
Step-by-step explanation: We are given two lines 'h' and 'k' which are parallel to each other. Also, there is another line 'j' that is perpendicular to line 'h'.
We are to prove that line 'j' is perpendicular to line 'k'.
Let, m, n and p be the slopes of lines 'h', 'k' and 'j' respectively.
Now, since line 'h' and 'k' are parallel, so their slopes will be equal. i.e., m = n.
Also, lines 'h' and 'j' are perpendicular, so the product of their slopes is -1. i.e.,
m×p = -1.
Hence, we can write from the above two relations
n×p = -1.
Thus, the line 'j' is perpendicular to line 'k'.
Proved.
Does not exist, since the graph of cosine is continuous between the intervals [-1,1]. You do not know where it will be when it “reaches” infinity
90% of what is 63....
0.90x = 63
x = 63 / 0.90
x = 70....so 70 ppl work at stalling printing