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Pani-rosa [81]
2 years ago
14

IF the sum of four times a number and four less than three times a number is seventeen what is the number

Mathematics
1 answer:
Virty [35]2 years ago
3 0

Answer: 3

Step-by-step explanation: This equation can be written as 4x+3x-4=17

We can now solve.

Moving the 4 to the other side (adding) and we get 21.

Now we have 4x+3x. Adding like terms, we get 7x = 21. Now we divide by 7.

X = 3.

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What is the number name of (i)46,25,689and (ii)658,902,250​
Solnce55 [7]

Answer:

forty six hundred thousand tweny five thound and six hundred eighty nine

six hundred and fifty eight hundred nine thoundsand two and two hundred and fifty

Step-by-step explanation:

5 0
2 years ago
You tell your mom that you want ₹700₹700₹, 700 as pocket money every month. She can deposit some money in the bank such that the
Colt1911 [192]
Let me think? I’m not sure
6 0
3 years ago
The labor force participation rate is the number of people in the labor force divided by the number of people in the country who
zepelin [54]

Answer:

The expected participation rate is 0.637.

The standard error is 0.04397

Step-by-step explanation:

For each working age people asked, there are only two possible outcomes. Either they are in the labor force, or they are not. This means that we can solve this problem using binomial distribution probability concepts.

Binomial probability:

Expected value for the participation rate: The expected value is the probability of a success. In this problem, a success is a working age people being in the labor force. 63.7% of them are. So \pi = 0.637. This means that the expected participation rate is 0.637.

Standard error for the participation rate:

The standard error is given by the following formula:

\sigma = \sqrt{\frac{\pi(1-\pi)}{n}}.

In this problem, 120 people are asked, so \pi = 120

s = \sqrt{n\pi(1-\pi)} = \sqrt{\frac{0.637*(1-0.637)}{120}} = 0.04397.

So the standard error is 0.04397

8 0
3 years ago
Read 2 more answers
Please calculate this limit <br>please help me​
Tasya [4]

Answer:

We want to find:

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n}

Here we can use Stirling's approximation, which says that for large values of n, we get:

n! = \sqrt{2*\pi*n} *(\frac{n}{e} )^n

Because here we are taking the limit when n tends to infinity, we can use this approximation.

Then we get.

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n} = \lim_{n \to \infty} \frac{\sqrt[n]{\sqrt{2*\pi*n} *(\frac{n}{e} )^n} }{n} =  \lim_{n \to \infty} \frac{n}{e*n} *\sqrt[2*n]{2*\pi*n}

Now we can just simplify this, so we get:

\lim_{n \to \infty} \frac{1}{e} *\sqrt[2*n]{2*\pi*n} \\

And we can rewrite it as:

\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n}

The important part here is the exponent, as n tends to infinite, the exponent tends to zero.

Thus:

\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n} = \frac{1}{e}*1 = \frac{1}{e}

7 0
3 years ago
Help what’s the answer
aivan3 [116]

Answer: 2⁴ * 5

<u>Step-by-step explanation:</u>

                    80

                     ∧

                  8    10

                 ∧      ∧

               4  2   2  5

               ∧        

              2  2

80: 2 x 2 x 2 x 2 x 5


7 0
2 years ago
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