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WITCHER [35]
3 years ago
9

My partner and i are at coordinates (−20, 15) on a map. if our destination is at coordinates (35, −12), (a) what are the coordin

ates of the rest station located halfway to our destination? (b) how far away is our destination? assume that each unit is 1 mi.
Mathematics
1 answer:
Scilla [17]3 years ago
4 0
The rest station is the midpoint of the given coordinates:
(-20+35)/2 , for the x value  and (15+-12)/2 for the y value.

Coordinates of the rest station: (7.5, 1.5)

How far is the destination? Use the distance formula : D² = √(x1-x2) + (y1-y2)
(-55)² + (27)² = D²   D = √3754 = 61.27
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Answer:

The exact answer in terms of radicals is x = 5*\sqrt[3]{25}

The approximate answer is x \approx 14.62009 (accurate to 5 decimal places)

===============================================

Work Shown:

Let y = \sqrt[5]{x^3}

So the equation reduces to  -7  = 8-3y

Let's solve for y

-7 = 8-3y

8-3y = -7

-3y = -7-8 ... subtract 8 from both sides

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y = -15/(-3) ... divide both sides by -3

y = 5

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Since y = \sqrt[5]{x^3} and y = 5, this means we can equate the two expressions and solve for x

y = 5

\sqrt[5]{x^3} = 5

x^3 = 5^5 Raise both sides to the 5th power

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x = \sqrt[3]{125*25}

x = \sqrt[3]{125}*\sqrt[3]{25}

x = \sqrt[3]{5^3}*\sqrt[3]{25}

x = 5*\sqrt[3]{25}

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