Use operations of decimal, fraction, and percent numbers to model the following scenarios. In your final answer, include only an
2 answers:
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The results of the survey are shown in the table.
It's required to calculate the following probabilities:
a) A customer is neutral
The row labeled as 'Neutral' has a total of 79 customers out of 367 in total.
The required probability is:
b) A customer is a walk-in
The first column labeled as 'Walk-in' has a total of 106 customers out of 367. The required probability is
c) A customer is dissatisfied and a walk-in.
We have to cross the row Dissatisfied with the column Walk-in. The number of customers that have both categories is 22 out of 367.
The required probability is:
d) A customer is very satisfied given he saw a TV ad.
This is a conditional probability, where the total is 111 because is the given condition. The customers that have both characteristics are 33, thus the required probability is:
e) A customer is satisfied or referred.
Total satisfied = 139
Total referred = 150
With both features = 62
Total customers with one or both features: 139 + 150 - 62 = 227
We have to subtract the common feature because it was counted twice.
The required probability is:
Step-by-step explanation:
a. Area of a circle = πr², where r means radius.
Step 1: converted diameter to radius.
diameter = 2 radius
In other way of writing, radius = diameter.
Step 2: substitute radius into the formula.
Area of a circle = π(d)²
Step 3: substitute π into the formula.
some question is given the value of π), if not substitute 3.14 for π.
Area of a circle = 3.14(d)²
Step 4: substitute d into the formula, then we can solve its area.
b. a. Circumference of a circle = 2πr, where r means radius.
Step 1: converted diameter to radius.
diameter = 2 radius
In other way of writing, radius = diameter.
Step 2: substitute radius into the formula.
C = 2π(d)
Step 3: substitute π into the formula.
some question is given the value of π), if not substitute 3.14 for π.
C = 2(3.14)(d)
Step 4: substitute d into the formula, then we can solve its circumference.