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Illusion [34]
3 years ago
6

PLEASE HELP ASAP! THANKS FOR HELPING IF U HELP

Mathematics
1 answer:
Sphinxa [80]3 years ago
6 0

Answer:

1st question: false

2nd question: true

3rd question: false

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The perimeter of a triangle is 65 meters. The second side is 5 meters less than the first side The third side is 7
tangare [24]

Answer:

The length of each side is 31.5m, 26.5m, 7m

Step-by-step explanation:

Let the length of the first side of the triangle be x meters.

Then, the second side is x-5 meters.

The third side is given as 7 meters.

The perimeter is 65 meters

This gives us the equation:

65 = x + x - 5 + 7

65 - 7 + 5 = x + x

63 = 2x

x =  \frac{63}{2}  = 31.5

The length of each side is 31.5m, 26.5m, 7m

4 0
4 years ago
2.1 If 5 + 3 = 0 and < 0, evaluate (without using a calculator):
Sergeeva-Olga [200]

1. 18

2.8

3.-1

<h3>What is expression?</h3>

An expression is a set of terms combined using the operations +, – , x or ,/.

Given:

1. 22 − 1 (4)

=22- 1*4

= 22-4

= 18

2. 2 + 2 (3)

=2+2*3

=2+6

=8

3. 1 − 2

= -1

Learn more about expression here:

brainly.com/question/14083225

#SPJ1

6 0
2 years ago
If you can answer this question you'll get brainliest.
igomit [66]

Answer:

Volume = 66 cm³

Step-by-step explanation:

Area of the oblique triangular prism = Area of the triangular base × Vertical height from the base

From the figure attached,

Area of the triangular base = \frac{1}{2}(\text{Base})(\text{Height of the right triangle})

                                             = \frac{1}{2}(3)(4)

                                             = 6 cm²

Vertical height of the given oblique prism = 11 cm

Volume of the given oblique prism = 6 × 11

                                                          = 66 cm³

4 0
3 years ago
Read 2 more answers
angle 0 is in quadrant 1 with sin0 = 2/5. Use the Pythagorean identity, sin^2 0 + cos^2 0 = 1, to calculate the value of cos0 as
Gwar [14]
We know that
sin²x+cos²x=1
so 
clear cos x
cos x=(+/-)√[1-sin²x]

in this problem
<span>Angle 0 is in quadrant 1 -----> cos o and sin o are positive
</span>sin o=2/5
cos x=√[1-(2/5)²]----> cos o=√[1-4/25]----> cos o=√[21/25]---> cos o=√21/5

the answer is
cos o=√21/5

7 0
3 years ago
Helpp please!!!
zavuch27 [327]

Answer:

  h, j2, f, g, j1, i, k, l (ell)

Step-by-step explanation:

The horizontal asymptote is the constant term of the quotient of the numerator and denominator functions. Generally, it it is the coefficient of the ratio of the highest-degree terms (when they have the same degree). It is zero if the denominator has a higher degree (as for function f(x)).

We note there are two functions named j(x). The one appearing second from the top of the list we'll call j1(x); the one third from the bottom we'll call j2(x).

The horizontal asymptotes are ...

  • h(x): 16x/(-4x) = -4
  • j1(x): 2x^2/x^2 = 2
  • i(x): 3x/x = 3
  • l(x): 15x/(2x) = 7.5
  • g(x): x^2/x^2 = 1
  • j2(x): 3x^2/-x^2 = -3
  • f(x): 0x^2/(12x^2) = 0
  • k(x): 5x^2/x^2 = 5

So, the ordering least-to-greatest is ...

  h (-4), j2 (-3), f (0), g (1), j1 (2), i (3), k (5), l (7.5)

6 0
3 years ago
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