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Greeley [361]
2 years ago
7

NO LINKS!! Please help me with this problem​

Mathematics
1 answer:
Fittoniya [83]2 years ago
6 0

Answer:

  • Mix A is 2 units
  • Mix B is 1 unit
  • Mix C is 3 units

Step-by-step explanation:

Let amount of Mix A is a, Mix B is b, Mix C is c.

<u>With the given details, we get the following system</u>

  • 5a + 6b + 4c = 28
  • 4a + 2b + c = 13
  • 3a + 4b + 4c = 22

Find the value of c (the easiest one) for substitution

  • c = 13 - 4a - b

Substitute c into the first equation

  • 5a + 6b + 4(13 - 4a - 2b) = 28
  • 5a + 6b + 52 - 16a - 8b = 28
  • - 11a - 2b = 28 - 52
  • 11a + 2b = 24      (5)

Substitute c into the third equation

  • 3a + 4b + 4(13 - 4a - 2b) = 22
  • 3a + 4b + 52 - 16a - 8b = 22
  • - 13a - 4b = 22 - 52
  • 13a + 4b = 30       (6)

Double the equation (5) and subtract (6), find the value of a

  • 2(11a + 2b) - 13a - 4b = 2(24) - 30
  • 22a - 13a = 48 - 30
  • 9a = 18
  • a = 2

Find b

  • 11*2 + 2b = 24
  • 22 + 2b = 24
  • 2b = 2
  • b = 1

Now find c

  • c = 13 - 4*2 - 2*1
  • c = 13 - 8 - 2
  • c = 3
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