The radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.
r= 24.
<h3>What is the radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.?</h3>
Generally, the equation for side lengths AB is mathematically given as
Triangle ABC has side lengths
Where
- AB = 65,
- BC = 33,
- AC = 56.
Hence
r √ 2 · (89 √ 2/2 − r √ 2) = r(89 − 2r),
r = 89 − 65
r= 24.
In conclusion, The radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.
r= 24.
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0.15 as fraction or multiply 3/8 and 2/5
Answer: x=-3/4
Step-by-step explanation:
Since we know f(x)=6, we can set it equal to the equation.
6=9+4x [subtract 9 on both sides]
-3=4x [divide both sides by 4]
x=-3/4
Yup, that right there is a math.
Answer:
h
Step-by-step explanation:
