Answer: The answer is attached in the figure.
Step-by-step explanation: Given are four different graphs and we are to check which one matches with the equation y = 2 - x.
We have the following points on this equation.
(0,2), (1,1), (2,0), etc.
When we try to match these points with the given graphs, the we see that these points does not match with the first, third and fourth graph. The only graph containing these points is second one.
Thus, the second option is correct. Also see the attached figure for the location of the three mentioned points.
D and E. If I remember right that should be the answer.
Answer:
A
Step-by-step explanation:
i just had this problem
Using the <em>normal distribution and the central limit theorem</em>, it is found that there is a 0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.
<h3>Normal Probability Distribution</h3>
In a normal distribution with mean 
and standard deviation 
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
- By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation
.
In this problem:
- The mean is of 660, hence
.
- The standard deviation is of 90, hence
.
- A sample of 100 is taken, hence
.
The probability that 100 randomly selected students will have a mean SAT II Math score greater than 670 is <u>1 subtracted by the p-value of Z when X = 670</u>, hence:
By the Central Limit Theorem
has a p-value of 0.8665.
1 - 0.8665 = 0.1335.
0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.
To learn more about the <em>normal distribution and the central limit theorem</em>, you can take a look at brainly.com/question/24663213
Answer:
1. P(5 U 6) =2/3
2. P(2 U 5 U 6) = 5/6
3. P(1 U 2) = 1/3
4. P(4) = 0
Step-by-step explanation:
As the number cube has 6 sides,
So,
Total outcomes = {1,2,5,5,6,6}
n(S) = 6
Now,
1. P(5U6) = P(5) + P(6)
P(5)=2/6=1/3
P(6)=2/6=1/3
P(5U6)= 1/3 + 1/3 = 2/3
2. P(2 U 5 U 6) = P(2) + P(5) + P(6)
P(2)=1/6
P(5)=2/6
P(6)=2/6
P(2 U 5 U 6) = 1/6 + 2/6 + 2/6
= 5/6
3. P(1 U 2) = P(1) + P(2)
P(1) = 1/6
P(2)= 1/6
P(1 U 2) = 1/6 + 1/6
= 2/6 = 1/3
4. P(4) = 0
As 4 is not in the outcomes, it's probability will be zero ..
