Answer:
Step-by-step explanation:
At first, the question looks like an optimization problem, but since all the dimensions of the carton are given, we only have to compute the total area of the given figure.
Let's calculate the front (and back) areas, which are rectangles
Now with the lateral rectangles which happen to have the very same dimensions
Next, we compute the front and back triangles of base 3 in and height 1.5 in
Now, the lateral inclined rectangles of base 3 in and height 2 in
Finally, the base rectangle who happens to be a square of side 3 in
This last area, unlike all others, is not doubled because its counterpart is inside the carton and is not part of the lateral area
Our total area of cardboard is
The closest option to this answer is
