How many times do you subtract 7 from 1999 and 5 from 1701 to get an equal number?

Mathematics

1 answer:

blsea [12.9K]2 years ago

5 0

Answer:

<h2>149 times.</h2>

Step-by-step explanation:

Let n be the number we are looking for.

The we have to solve this equation:

1999 - 7n = 1701 - 5n

⇔ 1999 - 1701 = 7n - 5n

⇔ 298 = 2 n

⇔ n = 298/2

⇔ n = 149

<u><em>Verification</em></u> :

1 999 - 7×149 = 956

1 701 - 5×149 = 956

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