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olga_2 [115]
2 years ago
14

How many times do you subtract 7 from 1999 and 5 from 1701 to get an equal number?

Mathematics
1 answer:
blsea [12.9K]2 years ago
5 0

Answer:

<h2>149 times.</h2>

Step-by-step explanation:

Let n be the number we are looking for.

The we have to solve this equation:

1999 - 7n = 1701 - 5n

⇔ 1999 - 1701 = 7n - 5n

⇔ 298 = 2 n

⇔ n = 298/2

⇔ n = 149

<u><em>Verification</em></u> :

1 999 - 7×149 = 956

1 701 - 5×149 = 956

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The logical way is to graph in polar coordinates. I did it using </span>a graphing software and obtained the attached graph.

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Here you have a table that you can build by your self and use the pairs to draw the graph (either cartesian or polar coordinates).

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3π/4          2.29289322 </span> <span>
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In both of the attached graphs you can see that the left side is equal to the right side, but the upper side is not equal to the bottom side.

Therefore, the graph is symmetric about the y-axis.





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