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Travka [436]
2 years ago
6

DO Tuesday Write 1,003,498 in each form. Word: Expanded: need help really please​

Mathematics
1 answer:
alukav5142 [94]2 years ago
8 0

word form: one million, three thousand, four hundred ninety eight

number form : 1,003,498

expaned form 1000000 + 30000 + 400 + 90 + 8

i would so base form but i cant

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The coach took a digital photo of the new cycling team bike. She sent a 4 cm-by-6 cm photo to each team
erastova [34]

Answer:

1. 9 cm

2. 50%

3. Assuming the photo is a rectangle, the answer would be 90 degrees on every angle (in a dilation, angle measurements are congruent).

Step-by-step explanation:

1. The long side is clearly the 6 cm side. multiply it by 1.5x (150%) and you get 9.

2. 2 is 50% of 4 and 3 is 50% of 6.

3. Assuming the photo is a rectangle, the answer would be 90 degrees on every angle (in a dilation, angle measurements are congruent).

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Betty stopped running half of the way through the run.
Serhud [2]
Desmond ran the further distance because Betty ran 2/4 and Desmond ran 3/4
6 0
3 years ago
Best explained and correct answer gets brainliest!
Norma-Jean [14]
It would be C, because a straight line equals to 180 degrees, and since 3 is 86, and lines m and n are parallel, 180-86 = C.94. Hope this helps! 
6 0
3 years ago
Multiple Choice Find<br> the value of x.<br> A 5 B 215<br> C 52 D 1<br> 10
olga_2 [115]

Answer:

5 x Square root:2

Step-by-step explanation:

7 0
3 years ago
NEED HELP Find values for a, b, c, and d so that the following matrix product equals the 2X2 identity matrix. Explain or show ho
ehidna [41]

We want to find the values of a, b, c, and d such that the given matrix product is equal to a 2x2 identity matrix. We will solve a system of equations to find:

  • b = 1
  • a = -1
  • c = -2
  • d = -1

<h3>Presenting the equation:</h3>

Basically, we want to solve:

\left[\begin{array}{cc}-1&2\\a&1\end{array}\right]*\left[\begin{array}{cc}b&c\\1&d\end{array}\right] = \left[\begin{array}{cc}1&0\\0&1\end{array}\right]

The matrix product will be:

\left[\begin{array}{cc}-b + 2&-c + 2d\\a*b + 1&a*c + d\end{array}\right]

Then we must have:

-b + 2 = 1

This means that:

b = 2 - 1 = 1

  • b = 1

We also need to have:

a*b + 1 = 0

we know the value of b, so we just have:

a*1 + b = 0

  • a = -1

Now the two remaining equations are:

-c + 2d = 0

a*c + d = 1

Replacing the value of a we get:

-c + 2d = 0

-c + d = 1

Isolating c in the first equation we get:

c = 2d

Replacing that in the other equation we get:

-(2d) + d = 1

-d = 1

  • d = -1

Then:

c  = 2d = 2*(-1) = -2

  • c = -2

So the values are:

  • b = 1
  • a = -1
  • c = -2
  • d = -1

If you want to learn more about systems of equations, you can read:

brainly.com/question/13729904

4 0
3 years ago
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