Answer:
C) There is not sufficient evidence to support the claim that the mean attendance is greater than 523.
Step-by-step explanation:
Let μ be the the average attendance at games of the football team
The claim: the average attendance at games is over 523
Null and alternative hypotheses are:
: μ=523
: μ>523
The conclusion is failure to reject the null hypothesis.
This means that <em>test statistic</em> is lower than <em>critical value</em>. Therefore it is not significant, there is no significant evidence to accept the <em>alternative</em> hypothesis.
That is no significant evidence that the average attendance at games of the football team is greater than 523.
Answer:
$68.48
Step-by-step explanation:
You want to find cost such that ...
6.25% × cost = $4.28
Dividing by the coefficient of cost, we get ...
cost = $4.28/0.0625 = $68.48
10, 000, 000 = ten million
40, 000 ,000 is the answer for the nearest ten million
Ok so the answer to this was a bit tricky but it is 1,8
Answer:
Picture please. and answer.