A 32 foot tall tree casts a shadow that is 48 feet long. How far away from the tree is a
1 answer:
Answer:
39 feet
Step-by-step explanation:
take the tree as AB , the distance between the man and the tree as BC, the distance between the man and the tip of the shadow CD and the point intersecting the hypotenuse CE
since CE parallel to AB we can BPT
CE/AB = CD/BD
6/32= CD/48
CD = 9 feet
since CD is feet
BC is 48-9 = 39 feet
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