What? ......
jsisjsjsididkdkdkdkdkdkkfkckckckckckckckckckckc
Let us solve for the total area. In this problem, we solve area 1 (the rectangle in the middle) and the area 2 ( the two half circle on the sides).
Solve for area 1:
Area rec = L * W = 5units * 4 units = 20 squared units
Solve for area 2:
Area cir = pi *r² = 3.14 * (2 units)² = 12.56 squared units
Total area = 20 + 12.56 = 32.56 foot²
Total cost = 32.56 foot² * ($23/foot²) = $ 748.88
Total cost is $748.88.
Answer:
8$
Step-by-step explanation:
4 students contribute 12$ Each.
So, total amount becomes 12 x 4 = 48$
If two more students contribute it makes a total of 6 students.
so we now divide the 48$ by 6
48/6=8$
The answer would be b.) angle C is congruent to angle E.
Hope this helps
The two planes are flying on the two legs of a right triangle.
The straight distance between them is the hypotenuse of the triangle.
Since the speeds are in mph, let's work the time in hours.
Call the time 'H' that we're looking for.
It's the number of hours after they both take off that they're 650 miles apart.
After 'H' hours, the first plane has gone 500H miles north.
After 'H' hours, the second plane has gone 1200H miles east.
After 'H' hours, they are 650 miles apart.
Do you remember this for a right triangle ? ==> A² + B² = C²
(500H)² + (1200H)² = (650)²
250,000H² + 1,440,000H² = 422,500
1,690,000 H² = 422,500
H² = (422,500) / (1,690,000) = 0.25
H = √0.25 = 1/2 hour = 30 minutes
