DUE TODAY PLEASE HELP.
1 answer:
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The picture in the attached figure
we have
arc XV = 68°∠YUV = 36°
we know that
The measure of the external angle is the semidifference of the arcs that it covers.
therefore
∠YUV =[arc VY-arc XV]/2
arc VY=[2*∠YUV]+arc XV----------> [2*36]+68---------> 140°
the answer is
the measure of arc VY is 140°
we have
arc XV = 68°∠YUV = 36°
we know that
The measure of the external angle is the semidifference of the arcs that it covers.
therefore
∠YUV =[arc VY-arc XV]/2
arc VY=[2*∠YUV]+arc XV----------> [2*36]+68---------> 140°
the answer is
the measure of arc VY is 140°
Answer:
#6 is 17 days
Step-by-step explanation:
This is how I answered it
1) 2750 = 550 + 125x
2) subtract 550 from each side
2750-550=2200
so the left over equation is:
2200 = 125x
3) divide each side by 125 to get x by itself
2200÷125= 17.6
4) you are left with: x = 17 days
The mean absolute deviation of the scuba diver’s depth over the entire 25 min is 2.4 meters
<h3>What is mean absolute deviation?</h3>It is defined as the measure to show the variation in data set in other words between the mean and every data value, the distance known as the MAD.
We have depths of the scuba diver, in meters
{−9, −18, −16, −13, −14}
We know the formula for the mean absolute deviation:
Here n is total number of observation
x is the elements in the data set
X is the mean of the data.
n = 5
x = -70/5 = -14
∑|x-X| = 12
MAD = 12/5 = 2.4 meters
Thus, the mean absolute deviation of the scuba diver’s depth over the entire 25 min is 2.4 meters.
Learn more about the mean absolute deviation here:
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