A.
9(1)+4=13
9(2)+4=22
9(3)+4=31
etc
Answer:
(b) 4,445
Step-by-step explanation:
If the researcher would like to be 95% sure that the obtained sample proportion would be within 1.5% of p (the proportion in the entire population of U.S. adults), what sample size should be used?
Given a=0.05, |Z(0.025)|=1.96 (check standard normal table)
So n=(Z/E)^2*p*(1-p)
=(1.96/0.015)^2*0.5*0.5
=4268.444
Take n=4269
Answer:(b) 4,445
Triangles PQR and PSR are right triangles, with both QR = SR = 5 (since these are radii of the circle R).
TR is also a radius of the circle, so TR = 5, making PR = 4 + TR = 9.
Because PQR and PSR are right triangles, we can compute the length of the missing side, which will be equal. By the Pythagorean theorem,
PQ^2 + QR^2 = PR^2
PQ^2 + 5^2 = 9^2
PQ^2 = 56
PQ = √56 = 2√14
Then the perimeter of PQRS is
PQ + QR + RS + SP = 2√14 + 5 + 5 + 2√14 = 10 + 4√14
and so the answer is B.
Answer:
84 is the highest possible course average
Step-by-step explanation:
Total number of examinations = 5
Average = sum of scores in each examination/total number of examinations
Let the score for the last examination be x.
Average = (66+78+94+83+x)/5 = y
5y = 321+x
x = 5y -321
If y = 6, x = 5×6 -321 =-291.the student cannot score -291
If y = 80, x = 5×80 -321 =79.he can still score higher
If If y = 84, x = 5×84 -321 =99.This would be the highest possible course average after the last examination.
If y= 100
The average cannot be 100 as student cannot score 179(maximum score is 100)
Answer:
The sum of a number and 7 multiplied by 2 is increased by 10
Step-by-step explanation:
