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castortr0y [4]
3 years ago
11

Which point is located at the origin? A B C D

Mathematics
2 answers:
Tresset [83]3 years ago
7 0
A is answer is 0,0<span>.On the flat coordinate plane, there are two axes, the vertical y-axis and the horizontal x-axis. The origin is the point where they intersect.</span>
Alina [70]3 years ago
4 0
A because the origin is at 0,0 and point A is at 0,0
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Which graph best represents the line y= -1/5x+2
vodomira [7]

Answer:

B

Step-by-step explanation:

Line crosses y-axis at 2.

Slope = \frac{-1}{5}

For each 1 square the line rises/falls it moves to the right/left 5 squares.

Negative slope lines are downhill left to right.  

8 0
3 years ago
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Alona [7]

a. 300x33+300x1

b. 10200

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7 0
2 years ago
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Refer to the figure below to complete the following problem.
Ratling [72]
Im pretty sure the answer id b
4 0
3 years ago
Please find the answer
Serggg [28]

Answer:

x^3 + 1/x^3 = 488

Step-by-step explanation:

  • x^2 + 1/x^2 = 62
  • x^2 + 1/x^2 + 2 = 64
  • ( adding 2 in both sides )
  • (x + 1/x ) ^2 = 64
  • x + 1/x = 8

now,

  • ( x+ 1/x ) ^ 3 = 512
  • x^3 + 1/x^3 + 3 × x × 1/x ( x + 1/x )
  • x^3 + 1/x^3 + 3 ( 8 )
  • ( since x + 1/x = 8 )
  • x^3 + 1/x^3 + 24 = 512
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hence, we got x^3 + 1/x^3 = 488

8 0
3 years ago
Lines AB and CD are straight lines. Find x and y. Give reasons to justify your solutions. I need both answers.
Kazeer [188]

Answer:

1) x = 14°, y = 5°

2) x = 18.5°, y = 37°

Step-by-step explanation:

1) ∠AOC and ∠BOD are vertical angles, then ∠BOD = 25°

∠MOD = ∠MOB + ∠BOD = 90°

3x + 23° + 25° = 90°

3x = 90° - 23° - 25°

x = 42°/3

x = 14°

∠LOB = ∠LOM + ∠MOB = 90°

5y + 3x + 23° = 90°

5y = 90° - 23° - 3(14°)

y = 25°/5

y = 5°

2) ∠AOC and ∠BOD are vertical angles, then ∠BOD = 16°

∠EOB = ∠EOD + ∠DOB =  90°

2y + 16° = 90°

y = (90° - 16°)/2

y = 37°

∠DOF = ∠BOF + ∠DOB =  90°

4x + 16° = 90°

x = (90° - 16°)/4

x = 18.5°

4 0
3 years ago
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