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Shtirlitz [24]
2 years ago
10

Consider that x = 1.5 and y = 3. Which statement is true about x + y?

Mathematics
1 answer:
ivann1987 [24]2 years ago
4 0

Answer:

x + y = 4.5

Step-by-step explanation:

x + y = 1.5 + 3 = 4.5

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What are the coordinators of the vertex of the graph of the function -2(x-1)^2 = y+5
mamaluj [8]
The answer is, (1, -5)... 
7 0
3 years ago
Checking account A charges a monthly service fee of $12 and a wire transfer fee of $10.50, while checking account B charges a mo
son4ous [18]

Answer:

checking account A is the better deal.

Step-by-step explanation:

A charges a monthly service fee = $12.00

Wire transfer fee = $10.50

B charges a monthly service fee = $21.00

Wire transfer fee = $8.50

If the requirement is four wire transfer per month

A charges for 4 wires = 10.50 × 4 = $42.00

and adding monthly service fees = 42.00  + 12.00 = $54.00

B charges for 4 wires = 8.50 × 4 = $34.00

and adding monthly service fees = 34.00 + 21.00 = $55.00

Therefore A charges less than B, so checking account A is the better deal.

3 0
2 years ago
Noah wants to put $1,000 in a savings account with a 1.5% annual interest rate. How much more money will he have after one year
larisa86 [58]
Assuming that 1.5% annual interest is converted to monthly basis with the same amount, then the monthly interest should be: 1.5%/12= 0.125%.

If you put $1000 for annual interest, the saving account would become: $1000*(100%+1.5%)= $1015

If you put $1000 for monthly interest, the saving account would become: ($1000*(100%+0.125%)= $1000*1.0151035559= $1015.10

Then, the money difference should be:  $1015.10-$1015= $0.10
6 0
3 years ago
Lee is replacing the carpet in the living room of the house. The living room is a rectangle 20 1/4 feet long 13 1/3 wide. A clos
gtnhenbr [62]

Answer:

100 ft

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Integrate this two questions ​
tankabanditka [31]

Simplify the integrands by polynomial division.

\dfrac{t^2}{1 - 3t} = -\dfrac19 \left(3t + 1 - \dfrac1{1 - 3t}\right)

\dfrac t{1 + 4t} = \dfrac14 \left(1 - \dfrac1{1 + 4t}\right)

Now computing the integrals is trivial.

5.

\displaystyle \int \frac{t^2}{1 - 3t} \, dt = -\frac19 \int \left(3t + 1 - \frac1{1-3t}\right) \, dt \\\\ = -\frac19 \left(\frac32 t^2 + t + \frac13 \ln|1 - 3t|\right) + C \\\\ = \boxed{-\frac{t^2}6 - \frac t9 - \frac{\ln|1-3t|}{27} + C}

where we use the power rule,

\displaystyle \int x^n \, dx = \frac{x^{n+1}}{n+1} + C ~~~~ (n\neq-1)

and a substitution to integrate the last term,

\displaystyle \int \frac{dt}{1-3t} = -\frac13 \int \frac{du}u \\\\ = -\frac13 \ln|u| + C \\\\ = -\frac13 \ln|1-3t| + C ~~~ (u=1-3t \text{ and } du = -3\,dt)

8.

\displaystyle \int \frac t{1+4t} \, dt = \frac14 \int \left(1 - \frac1{1+4t}\right) \, dt \\\\ = \frac14 \left(t - \frac14 \ln|1 + 4t|\right) + C \\\\ = \boxed{\frac t4 - \frac{\ln|1+4t|}{16} + C}

using the same approach as above.

5 0
2 years ago
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