Complete question is;
The terminal side of angle θ in standard position, intersects the unit circle at P(-10/26, -24/26). What is the value of csc θ?
Answer:
csc θ = -13/12
Step-by-step explanation:
We know that in a unit circle;
(x, y) = (cos θ, sin θ)
Since the the terminal sides intersects P at the coordinates P(-10/26, -24/26), we can say that;
cos θ = -10/26
sin θ = -24/26
Now we want to find csc θ.
From trigonometric ratios, csc θ = 1/sin θ
Thus;
csc θ = 1/(-24/26)
csc θ = -26/24
csc θ = -13/12
Step-by-step explanation:
First, add or subtract both sides of the linear equation by the same number.
Secondly, multiply or divide both sides of the linear equation by the same number.
Answer:
12
Step-by-step explanation:
its not 12 im just trying to make an account
The slope of a line is always zero because the line does not move up or down on the y-axis.
