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PIT_PIT [208]
3 years ago
12

Is (x+7) a factor of f(x)= x^3-3x^2+2x-8

Mathematics
1 answer:
nikklg [1K]3 years ago
6 0

Answer:

Step-by-step explanation:

Use synthetic division to answer this.  If the remainder is zero, then we can safely assume the divisor (x + 7) is a factor of the polynomial f(x)= x^3-3x^2+2x-8.

We use -7 as the divisor in synth. div.  This comes from the factor (x + 7):

-7   /    1    3     2     -8

               -7   28  -210

     -------------------------

         1      -4   30   -218

Here, the remainder is -218, not zero, so no, (x+7) is not a factor of f(x)= x^3-3x^2+2x-8.

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If the current in a circuit is 2 +j2 amps and the resistance is 3-j2 ohms, what is the voltage
victus00 [196]

Answer:

The voltage is 10 + 2j volts.

Step-by-step explanation:

Ohm's first law:

By Ohm's first law, the voltage is the multiplication of the current by the resistance, that is:

V = R*i

The voltage is measured in Volts, the current in amps and the resistance in ohms.

In this question:

Both the current and the resistance have complex parts. We have to know that:

j^{2} = -1

We have that:

R = 3 - 2j, i = 2 + 2j

Then

V = R*i

V = (3 - 2j)*(2 + 2j)

V = 6 + 6j - 4j - 4j^{2}

V = 6 + 2j - 4(-1)

V = 10 + 2j

The voltage is 10 + 2j volts.

4 0
3 years ago
Give me three numbers greater than 20 that I have 9 as a factor
Andrew [12]
27, 36, 45...all have factors of 9 and r greater then 20
8 0
3 years ago
Read 2 more answers
Find the point of intersection of the pair of straight lines<br> Y= -7x - 4<br> -y = 8x + 9
Aleonysh [2.5K]

Answer:

(-5,31)

Step-by-step explanation:

See image.

4 0
3 years ago
1 and 11 16s times 4 over 5
tia_tia [17]

Answer:

1 and 7/20 or in a decimal 1.35

Step-by-step explanation:

times the numerator and the denominator then simplify.

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8 0
3 years ago
George believes the Art Club students at his school have an unfair advantage in being assigned to the art class they request. He
Whitepunk [10]

Answer:

  class assignment seems to discriminate against Art Club members

Step-by-step explanation:

The probability of getting the requested assignment given that the student was in Art Club was ...

  P(got class | art club) = P(got class & art club)/P(art club)

  P(got class | art club) = (100/500)/(165/500) ≈ 60.6%

__

  P(got class | not club) = P(got class & not club)/P(not club)

  P(got class | not club) = (265/500)/(335/500) ≈ 79.1%

It looks like George's theory may be incorrect, as a significantly greater percentage of non-club students got their requested class than did club students. The class assignment process and art club membership are not independent, suggesting an unfair disadvantage for club students.

4 0
3 years ago
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