3 years ago

Is (x+7) a factor of f(x)= x^3-3x^2+2x-8

Mathematics

1 answer:

nikklg [1K]3 years ago

6 0

Answer:

Step-by-step explanation:

Use synthetic division to answer this. If the remainder is zero, then we can safely assume the divisor (x + 7) is a factor of the polynomial f(x)= x^3-3x^2+2x-8.

We use -7 as the divisor in synth. div. This comes from the factor (x + 7):

-7 / 1 3 2 -8

-7 28 -210

-------------------------

1 -4 30 -218

Here, the remainder is -218, not zero, so no, (x+7) is not a factor of f(x)= x^3-3x^2+2x-8.

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If < A and < B are vertical angles, and < A = 2x - 11 degrees, and < B = x + 7 degrees, find x.

Tema [17]

Answer:

x=18

Step-by-step explanation:

Vertical angles are congruent. This means that they are equal to each other. So, to solve set them equal to each other and isolate x. First, set up the equation. Then, subtract x from both sides. Finally, add 11 to both sides and simplify.

1) $2x-11=x+7$