Your domain is all positive numbers, and your range is all numbers. this is because no matter what you plug in for y, x will only ever get extremely close to 0, but never reach it or go below it, and if you put in large values of y x will get very big.
Answer:
35.25
Step-by-step explanation:
Give the data set:
23 37 49 34 35 41 40 26 32 22 38 42
We are expected to calculate the midquartile of the given data set.
22 23 26 32 34 35 37 38 40 41 42 49
First step is to find the lower quartile which comprises of
22 23 26 32 34 35
Here the Q1 is (26+32)/2 = 58/2= 29
Second step to find the upper quartile which comprises of
37 38 40 41 42 49
Here the Q3 is (40+41) /2 = 81/2 = 41.5
Then to find the midquartile which is (Q1+Q3) /2 where Q1 is 29 and Q3 is 41.5
= (29+41.5)/2
= (70.5) /2 = 35.25
The complete factorisation of 50a²b⁵ − 35a⁴b³ + 5a³b⁴ is 5a²b³(10b² - 7a² + ab)
<h3>How to factorise?</h3>
Factorisation is the process of writing an expression as a product of two or more common factors.
The expression is written as a product of several factor.
Therefore,
50a²b⁵ − 35a⁴b³ + 5a³b⁴
Hence, the complete factorisation is as follows;
5a²b³(10b² - 7a² + ab)
learn more on factorisation here: brainly.com/question/2272501
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Answer:
∠F ≈ 53°
General Formulas and Concepts:
<u>Trigonometry</u>
- sin∅ = opposite over hypotenuse
- sin inverse evaluates "backward" to find the measure angle
Step-by-step explanation:
<u>Step 1: Define</u>
Looking at ∠F
opposite leg of ∠F = ED = 8
hypotenuse = FE = 10
<u>Step 2: Find m∠F</u>
- Substitute: sin∠F = 8/10
- Simplify: sin∠F = 4/5
- Take sin inverse: ∠F = sin⁻¹(4/5)
- Evaluate: ∠F = 53.1301°
- Round: ∠F ≈ 53°
Answer:
There are two types of similar triangle problems; these are problems that require you to prove whether a given set of triangles are similar and those that require you to calculate the missing angles and side lengths of similar triangles. Subtract both sides by 130°. Hence; By Angle-Angle (AA) rule, ΔPQR~ΔXYZ.
Step-by-step explanation: