25.8%
First, determine how many standard deviations from the norm that 3 tons are. So:
(3 - 2.43) / 0.88 = 0.57/0.88 = 0.647727273
So 3 tons would be 0.647727273 deviations from the norm. Now using a standard normal table, lookup the value 0.65 (the table I'm using has z-values to only 2 decimal places, so I rounded the z-value I got from 0.647727273 to 0.65). The value I got is 0.24215. Now this value is the probability of getting a value between the mean and the z-score. What I want is the probability of getting that z-score and anything higher. So subtract the value from 0.5, so 0.5 - 0.24215 = 0.25785 = 25.785%
So the probability that more than 3 tons will be dumped in a week is 25.8%
Answer:
p = 39 f = 44
Step-by-step explanation:
p = $ 1.73
f = $ 1.44
<u><em>equation </em></u>
p + f = 83
1.73 p + 1.44 (83 - p) = $ 130.83
p = 39 (amount of times fruit pies were sold).
Therefore,
<em>p = 39</em>
<em>f = 44</em>
Look it up on the internet youll find the answer there i am only learining about adding integers right now
Answer:
49.5
Step-by-step explanation:
just put into you calculator
47+(15/3)/2
