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3 years ago

13

A real number between 13 and 14

1 answer:

Nataly_w [17]3 years ago

3 0

Answer:

13.6

Hope this helped

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I need helpppppp.....

natita [175]

Answer:

i think its 7.28

Step-by-step explanation:

6 0

2 years ago

Write the expression in the simplest terms (x^2-10)+(10^2+2)

Leto [7]

X^2+92 is the simplest form first solve the second parentheses. 10^2+2=102 then add -10. 102+-10 is the same as 102-10=92 plug back in x^2+92.

6 0

3 years ago

Find the 12th term of the geometric sequence 5, -25, 125, ...5,−25,125,...

katovenus [111]

Answer:

$a_{12}=-244140625$

Step-by-step explanation:

Considering the geometric sequence

$5,-25,\:125,\:...$

$a_1=5$

As the common ratio ' $r$ ' between consecutive terms is constant.

$\mathrm{Compute\:the\:ratios\:of\:all\:the\:adjacent\:terms}:\quad \:r=\frac{a_{n+1}}{a_n}$

$r=\frac{-25}{5}=-5$

$r=\frac{125}{-25}=-5$

The general term of a geometric sequence is given by the formula:

$a_n=a_1\cdot \:r^{n-1}$

where $a_1$ is the initial term and $r$ the common ratio.

Putting $n = 12$ , $r = -5$ and $a_1=5$ in the general term of a geometric sequence to determine the 12th term of the sequence.

$a_n=a_1\cdot \:r^{n-1}$

$a_n=5\left(-5\right)^{n-1}$

$a_{12}=5\left(-5\right)^{12-1}$

$=5\left(-5^{11}\right)$

$\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a$

$=-5\cdot \:5^{11}$

$\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}$

$=-5^{1+11}$ ∵ $5\cdot \:5^{11}=\:5^{1+11}$

$=-244140625$

Therefore,

$a_{12}=-244140625$

6 0

2 years ago

Helppp! Is Figure A’B’C’D’ a reflection of Figure ABCD? Explain. *

Korolek [52]

Yes. It would be a reflection over the line.

8 0

2 years ago

3. Kanyla makes and

Triss [41]

Answer:

$23

Step-by-step explanation:

1 phone case = $12

4 phone cases = 12 * 4 = $48

Table = $25

4 phone cases - Table = 48 - 25 = $23

4 0

2 years ago

Read 2 more answers