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umka2103 [35]
3 years ago
14

H(n) = -2n² + 4; Find h(4)A.-28B.68C.28D.-4​

Mathematics
1 answer:
Elena L [17]3 years ago
7 0

Answer:

-28

Step-by-step explanation:

h(4)=-2(4)^2+4

-32+4=-28

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Please help helpppppp
Deffense [45]
Your hand looks nice... 

Anyway, 11/4 is the answer


5 0
3 years ago
Which statement is best represented by the inequality c greater-than 3 and one-half?
luda_lava [24]

Answer: Chef Andre used more than 3 and one-half cups of flour.

Step-by-step explanation:

This is the > ‘greater than sign. For the question, we are to get the inequality that shows that"c is greater-than 3 and one-half".

Let Chef Andre be represented by c. Greater than is used to denote a situation when something is."more than" another thing. In this scenario,

Chef Andre used more than 3 and one-half cups of flour. This can be represented as C > 3 1/2.

This is the correct answer.

3 0
3 years ago
Read 2 more answers
What is -2 = 5 / (2x+3)
LUCKY_DIMON [66]

Answer:

x = -11/4

Step-by-step explanation:

Given that:

-2 = 5 / (2x+3)

Multiplying both sides by (2x + 3)

-2(2x + 3) = 5

"-" sign will alter the inner signs

-4x -6 = 5

Adding 6 on both sides:

-4x -6 +6 = 5 + 6

-4x  = 11

Dividing both sides by -4

-4x/-4 = 11/-4

x = -11/4

i hope it will help you!

3 0
3 years ago
How to solve this (complex fraction)
Leviafan [203]
1/4+5/4=1.5
1.5 divided by 4 = 0.5625
7 0
3 years ago
Read 2 more answers
A drug used to relieve anxiety and nervousness has a half-life of 16 hours. if a doctor prescribes one 2.8-milligram every 24 ho
dlinn [17]

After 24 hours, 35.4% of the initial dosage remains on the body.

<h3>What percentage of the last dosage remains?</h3>

The exponential decay is written as:

f(x) = A*e^{-k*x}

Where A is the initial value, in this case 2.8mg.

k is the constant of decay, given by the logarithm of 2 over the half life, in this case, is:

k = ln(2)/16h

Replacing all that in the above formula, and evaluating in x = 24 hours we get:

f(24h) = 2.8mg*e^{-24h*ln(2)/16h} = 0.9899 mg

The percentage of the initial dosage that remains is:

P = \frac{0.9899mg}{2.8mg}*100\% = 35.4\%

If you want to learn more about exponential decays:

brainly.com/question/11464095

#SPJ1

8 0
2 years ago
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