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jeka57 [31]
2 years ago
9

A current of 2A flows for 2minutes through the wire in a motor. (1) how much charge passes through a wire this time​

Physics
1 answer:
joja [24]2 years ago
3 0

Answer:

240 C

Explanation:

Given:

  • I = 2A
  • t = 2 minutes = 120 seconds

To find:

  • Charge passing through the wire (Q)

Solution: Formula relating Q, I and t is given as:

  • Q = It
  • Plugging the values of I and t in the above equation, we find:
  • Q = 2 * 120
  • -> Q = 240 C

Thus, 240 Coulomb charge will pass through the wire.

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Assume you have a rocket in Earth orbit and want to go to Mars. The required change in velocity is ΔV≈9.6km/s . There are two op
Nostrana [21]

Answer: Part 1: Propellant Fraction (MR) = 8.76

Part 2: Propellant Fraction (MR) = 1.63

Explanation: The Ideal Rocket Equation is given by:

Δv = v_{ex}.ln(\frac{m_{f}}{m_{e}} )

Where:

v_{ex} is relationship between exhaust velocity and specific impulse

\frac{m_{f}}{m_{e}} is the porpellant fraction, also written as MR.

The relationship v_{ex} is: v_{ex} = g_{0}.Isp

To determine the fraction:

Δv = v_{ex}.ln(\frac{m_{f}}{m_{e}} )

ln(MR) = \frac{v}{v_{ex}}

Knowing that change in velocity is Δv = 9.6km/s and g_{0} = 9.81m/s²

<u>Note:</u> Velocity and gravity have different measures, so to cancel them out, transform km in m by multiplying velocity by 10³.

<u />

<u>Part 1</u>: Isp = 450s

ln(MR) = \frac{v}{v_{ex}}

ln(MR) = \frac{9.6.10^{3}}{9.81.450}

ln (MR) = 2.17

MR = e^{2.17}

MR = 8.76

<u>Part 2:</u> Isp = 2000s

ln(MR) = \frac{v}{v_{ex}}

ln (MR) = \frac{9.6.10^{3}}{9.81.2.10^{3}}

ln (MR) = 0.49

MR = e^{0.49}

MR = 1.63

8 0
3 years ago
Which of the following best explains why electrical wires are usually covered with plastic or rubber
xeze [42]
Because plastic and rubber are insulators.
5 0
4 years ago
Read 2 more answers
A spring (k = 200 N/m) is fixed at the top of a frictionless plane inclined at angle θ = 33 °. A 1.2 kg block is projected up th
Serga [27]

Answer:

Explanation:

Initial kinetic energy = 29 J

work done against gravity = mgsin33 x d  , m is mass of the block

= 1.2 x 9.8 sin 33 x .9

= 5.76 J

potential energy stored in compressed spring

= 1/2 k x², k is spring constant and x is compression

= .5 x 200 x .3²

= 9

energy left = 29 - ( 5.76 + 9 )

= 14.24 J

b )

energy stored in spring when compression is .4 m

= 1/2 x 200 x .4²

= 16 J

required kinetic energy = 16 + 5.76

= 21.76 J

Block must be projected with energy of 21.76 J .

7 0
3 years ago
A motor must lift a 1500-kg elevator cab. The cab's maximum occupant capacity is 400 kg, and its constant "cruising" speed is 1.
natka813 [3]

Answer:

12900 W

24200 W

Explanation:

Given:

v₀ = 0 m/s

v = 1.3 m/s

t = 2.0 s

Find: a and Δx

v = at + v₀

(1.3 m/s) = a (2.0 s) + (0 m/s)

a = 0.65 m/s²

Δx = ½ (v + v₀) t

Δx = ½ (1.3 m/s + 0 m/s) (2.0 s)

Δx = 1.3 m

While accelerating:

Newton's second law:

∑F = ma

F − mg = ma

F = m (g + a)

F = (1500 kg + 400 kg) (9.8 m/s² + 0.65 m/s²)

F = 19855 N

Power = work / time

P = W / t

P = Fd / t

P = (19855 N) (1.3 m) / (2.0 s)

P ≈ 12900 W

At constant speed:

Newton's second law:

∑F = ma

F − mg = 0

F = mg

F = (1500 kg + 400 kg) (9.8 m/s²)

F = 18620 N

Power = work / time

P = W / t

P = Fd / t

P = Fv

P = (18620 N) (1.3 m/s)

P ≈ 24200 W

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Where is the best place to put pfds while you are out on your boat?
Alexeev081 [22]
The best place to put PFDs while you are out on your boat is at the top deck of your boat. PFDs must be placed at an area where it is easily accessible, especially in times of accidents, without any unnecessary gear or objects covering the PFDs, but it is best to wear a life jacket during the whole duration of the boat trip.
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3 years ago
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