Answer:
A
Explanation:
the answer would be basicly A
Answer:
Average speed = 0.35 m/s
Explanation:
Given the following data;
Distance = 1.3 Km
Time = 62 minutes
To find the average speed in m/s;
First of all, we would convert the quantities to their standard unit (S.I) of measurement;
Conversion:
1.3 kilometres to meters = 1.3 * 1000 = 1300 meters
For time;
1 minute = 60 seconds
62 minutes = X
Cross-multiplying, we have;
X = 62 * 60
X = 3720 seconds
Now, we can calculate the average speed in m/s using the formula;


Average speed = 0.35 m/s
Let's say the distance is D. Then the time going is D/10 sec. The time returning is D/20 s. The total time is 3D/20 s, and the total distance is 2D. The average speed for the round trip is (total distance)/(total time). That's (2D) ÷ (3D/20). That's (40D/3D) which is 13-1/3 m/s. (I thought it was going to depend on the distance, but it doesn't.)
Answer: velocity = 50m/s
Distance moved=5m
Explanation:
Using the formula Ft=Mv i.e impulse= momentum
Where F= force ,t= time, M= mass, v = velocity
In this case we need to find v,
F,t,M are all given in the question.
Therefore, substituting the values we have
250N×0.1s=0.5kg×v. Mass=500g= 0.5kg
v=25/0.5= 50m/s
The distance the puck will move when it is on his stick.
D= Velocity × time
D=50m/s × 0.1s
D=5m
Goodluck...
Answer:
R = 6.8
Explanation:
Given data:
Richter scale
where R - magnitude of earthquake of Richter scale
I - quake's intensity 
- minimum intensity earthquake
Plugging all information in the equation to get Richter's scale


R = 6.8