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DerKrebs [107]
3 years ago
12

Ilke is deciding whether to take his girlfriend on a dinner date or on a movie date the probability of this having a successful

dinner is 55%. the probability of this having a successful movie day is 0.45.
Which of these events is more likely?
Mathematics
1 answer:
Lerok [7]3 years ago
5 0

Answer:

The dinner date

Step-by-step explanation:

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When you divide the number of permutations of 11 objects taken 3 at a time by​ 3!, you will get the number of combinations of 11
Sloan [31]

Answer:

Yes

Step-by-step explanation:

Permutation :

nPr = n! ÷ (n - r)!

nCr = n! ÷ (n-r)!r!

11 objects taken 3 at a time :

11P3 = 11! ÷ (11 - 3)!

11P3 = 11! / 8!

11P3 = (11 * 10 * 9 )

11P3 = 990

Dividing by 3!

3! = 3*2*1 = 6

= 990 / 6

= 165

For combination :

11C3 = 11! ÷ 8!3!

11C3 = (11 * 10 * 9) / (3 * 2 * 1)

11C3 = 990 / 6

11C3

4 0
3 years ago
A right triangle has the following vertices (7,-3), (4,-3), (4,9) find the area of a right triangle
laila [671]

Answer:

Step-by-step explanation:

6 0
4 years ago
Read 2 more answers
In ΔIJK, k = 7.6 cm, j = 7.5 cm and ∠J=116°. Find all possible values of ∠K, to the nearest 10th of a degree.
Andre45 [30]

Answer:

No Possible Triangles

Step-by-step explanation:

Deltamath

7 0
3 years ago
Can someone please help me with 13 and 14, please show work, thx :)
Shalnov [3]
13.
1st: split the 1 shape into 2 shapes. (spit across to where you see one right angle(top), and a trapezoid(bottom)

2nd: now what i did was fill that gap to where the total height is 9 and the total length is 7. ( if you don't want to do that it is fine )

3rd: for the top do 5 times 2 = 10

4th: for the bottom do 4 times 5 = 20

5th: add 10 (top) and 20 (bottom) = 30
7 0
3 years ago
A data set includes data from 500 random tornadoes. The display from technology available below results from using the tornado l
solniwko [45]

Question:

The question is incomplete. The display technology was not given. Find below the complete question and the answers.

Display from technology:

Hypothesis Test Results

μ : Mean of variable      

H₀ : μ=2.7 miles

HA  : μ >2.7 miles

Variable     Sample Mean      Std. Err.        DF           T-Stat            P-value

Length            3.23601        0.285185      499        2.230166        0.0131

Step-by-step explanation:

From the result obtained, we have;

Null hypothesis:   H₀ : μ=2.7 miles

Alternative hypothesis:   HA  : μ >2.7 miles

Test statistics = 2.230166

P-value =  0.0131

Significant level: α = 0.05

Since the P value is less than the significance level, we can reject the null hypothesis.

There is no sufficient evidence to support the claim that the mean tornado length is greater than 2.7 miles

3 0
4 years ago
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