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blagie [28]
3 years ago
6

PLEASE HELP ME

Mathematics
1 answer:
olga_2 [115]3 years ago
7 0

The measure of the angles are ∠A = 91°, ∠C = 89° and ∠D = 34°

Explanation:

Given that the quadrilateral ABCD is inscribed in a circle.

The given angles are ∠A = (2x + 3), ∠C  = (2x + 1) and ∠D = (x - 10)

We need to determine the measures of the angles A, C and D

<u>The value of x:</u>

We know that, the opposite angles of a cyclic quadrilateral add up to 180°

Thus, we have,

\angle A+\angle C=180^{\circ}

Substituting the values, we have,

2x+3+2x+1=180

             4x+4=180

                   4x=176

                     x=44

Thus, the value of x is 44.

<u>Measure of ∠A:</u>

Substituting x=44 in ∠A = (2x + 3)°, we get,

\angle A=(2(44)+3)^{\circ}

     =(88+3)^{\circ}

\angle A=91^{\circ}

Thus, the measure of angle A is 91°.

<u>Measure of ∠C :</u>

Substituting x=44 in ∠C = (2x + 1)°, we get,

\angle C=(2(44)+1)^{\circ}

     =(88+1)^{\circ}

\angle C=89^{\circ}

Thus, the measure of angle C is 89°.

<u>Measure of ∠D :</u>

Substituting x=44 in ∠D = (x - 10)°, we get,

\angle D=(44-10)^{\circ}

\angle D=34^{\circ}

Thus, the measure of angle D is 34°.

Hence, the measure of the angles are ∠A = 91°, ∠C = 89° and ∠D = 34°

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