Question

PLEASE HELP ME

Answer 1

The measure of the angles are ∠A = 91°, ∠C = 89° and ∠D = 34°

Explanation:

Given that the quadrilateral ABCD is inscribed in a circle.

The given angles are ∠A = (2x + 3), ∠C  = (2x + 1) and ∠D = (x - 10)

We need to determine the measures of the angles A, C and D

The value of x:

We know that, the opposite angles of a cyclic quadrilateral add up to 180°

Thus, we have,

$\angle A+\angle C=180^{\circ}$

Substituting the values, we have,

$2x+3+2x+1=180$

             $4x+4=180$

                   $4x=176$

                     $x=44$

Thus, the value of x is 44.

Measure of ∠A:

Substituting $x=44$ in ∠A = (2x + 3)°, we get,

$\angle A=(2(44)+3)^{\circ}$

     $=(88+3)^{\circ}$

$\angle A=91^{\circ}$

Thus, the measure of angle A is 91°.

Measure of ∠C :

Substituting $x=44$ in ∠C = (2x + 1)°, we get,

$\angle C=(2(44)+1)^{\circ}$

     $=(88+1)^{\circ}$

$\angle C=89^{\circ}$

Thus, the measure of angle C is 89°.

Measure of ∠D :

Substituting $x=44$ in ∠D = (x - 10)°, we get,

$\angle D=(44-10)^{\circ}$

$\angle D=34^{\circ}$

Thus, the measure of angle D is 34°.

Hence, the measure of the angles are ∠A = 91°, ∠C = 89° and ∠D = 34°