Answer
a) y | p(y)
25 | 0.8
100 | 0.15
300 | 0.05
E(y) = ∑ y . p(y)
E(y) = 25 × 0.8 + 100 × 0.15 + 300 × 0.05
E(y) = 50
average class size equal to E(y) = 50
b) y | p(y)
25 | 
100 | 
300 | 
E(y) = ∑ y . p(y)
E(y) = 25 × 0.4 + 100 × 0.3 + 300 × 0.3
E(y) = 130
average class size equal to E(y) = 130
c) Average Student in the class in a school = 50
Average student at the school has student = 130
Answer:
12 rolls
Step-by-step explanation:
Jason wants to cut roll into pieces that are each 1/2 inches thick. 1/2 is equal to 0.5, so thickness of each roll is 0.5 inches
Total length of the roll is 6 inches. We have to find how many small 0.5 inch rolls can he cut.
In simple words we can say that we have to find: how many 0.5 inches can be out from 6 inches. This type of problem is solved by division. Dividing 6 inches by 0.5 inches will give us: How many 0.5 inches can be cut out from 6 inches i.e. how many 0.5 inches roll can be made from 6 inches roll
6 divided by 0.5 is 12.
This means Jason can cut 12 rolls of sausages each with thickness of 0.5 inches from a roll of 6 inches.
Hi,
Following the rules of PEMDAS you first subtract in the parentheses.
(5-2)=3
Then multiply the parentheses.
(3)(-6)=-18
Solve the exponent.
-4^2=16
Then you add -18 and 16 to get -2.
So the answer is B.-2.
I hope this helps.
Answer:
The last one :{(5, 0), (0, 1), (5, 2), (4,4)}
Step-by-step explanation:
