All categories

3 years ago

Use the graph to find the factorization of x2 - 6x + 8.

Mathematics

1 answer:

WARRIOR [948]3 years ago

4 0

Answer:

D. (x-2)(x-4)

Step-by-step explanation:

The graph cross the x-axis in points with x-coordinates of 2 and 4

then 2 and 4 are roots of x² - 6x + 8.

You might be interested in

Which unit of measure is the most reasonable to measure the length of your pet hamster?

Viktor [21]

Inches is the correct answer

7 0

3 years ago

Read 2 more answers

What is the surface area of the cylinder in terms of ? The diagram is not drawn to scale.

Delicious77 [7]

Answer:

SA = 748π in²

General Formulas and Concepts:

Symbols

π (pi) ≈ 3.14

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Geometry

Surface Area of a Cylinder Formula: SA = 2πrh + 2πr²

r is radius
h is height

Step-by-step explanation:

Step 1: Define

Identify variables

r = 11 in

h = 23 in

Step 2: Find Surface Area

Substitute in variables [Surface Area of a Cylinder Formula]: SA = 2π(11 in)(23 in) + 2π(11 in)²
Evaluate exponents: SA = 2π(11 in)(23 in) + 2π(121 in²)
Multiply: SA = 506π in² + 242π in²
Add: SA = 748π in²

7 0

3 years ago

(4, -3), (x, 1); slope -4

Alexandra [31]

Answer:

x = 3

Step-by-step explanation:

$m = \frac{y \frac{}{2} - y \frac{}{1} }{x \frac{}{2} - x \frac{}{1} }$

m = slope

x, y = coordinates

$- 4 = \frac{1 - ( - 3)}{x - 4} \\ - 4(x - 4) = 1 + 3 \\ - 4x + 16 = 4 \\ - 4 x = 4 - 16 \\ - 4x = - 12 \\ x= \frac{ - 12}{ - 4} \\ x = 3$

3 0

3 years ago

Find the volume of the solid.

dmitriy555 [2]

In Cartesian coordinates, the region (call it $R$ ) is the set

$R = \left\{(x,y,z) ~:~ x\ge0 \text{ and } y\ge0 \text{ and } 2 \le z \le 4-x^2-y^2\right\}$

In the plane $z=2$ , we have

$2 = 4 - x^2 - y^2 \implies x^2 + y^2 = 2 = \left(\sqrt2\right)^2$

which is a circle with radius $\sqrt2$ . Then we can better describe the solid by

$R = \left\{(x,y,z) ~:~ 0 \le x \le \sqrt2 \text{ and } 0 \le y \le \sqrt{2 - x^2} \text{ and } 2 \le z \le 4 - x^2 - y^2 \right\}$

so that the volume is

$\displaystyle \iiint_R dV = \int_0^{\sqrt2} \int_0^{\sqrt{2-x^2}} \int_2^{4-x^2-y^2} dz \, dy \, dx$

While doable, it's easier to compute the volume in cylindrical coordinates.

$\begin{cases} x = r \cos(\theta) \\ y = r\sin(\theta) \\ z = \zeta \end{cases} \implies \begin{cases}x^2 + y^2 = r^2 \\ dV = r\,dr\,d\theta\,d\zeta\end{cases}$

Then we can describe $R$ in cylindrical coordinates by

$R = \left\{(r,\theta,\zeta) ~:~ 0 \le r \le \sqrt2 \text{ and } 0 \le \theta \le\dfrac\pi2 \text{ and } 2 \le \zeta \le 4 - r^2\right\}$

so that the volume is

$\displaystyle \iiint_R dV = \int_0^{\pi/2} \int_0^{\sqrt2} \int_2^{4-r^2} r \, d\zeta \, dr \, d\theta \\\\ ~~~~~~~~ = \frac\pi2 \int_0^{\sqrt2} \int_2^{4-r^2} r \, d\zeta\,dr \\\\ ~~~~~~~~ = \frac\pi2 \int_0^{\sqrt2} r((4 - r^2) - 2) \, dr \\\\ ~~~~~~~~ = \frac\pi2 \int_0^{\sqrt2} (2r-r^3) \, dr \\\\ ~~~~~~~~ = \frac\pi2 \left(\left(\sqrt2\right)^2 - \frac{\left(\sqrt2\right)^4}4\right) = \boxed{\frac\pi2}$

3 0

1 year ago

What is the slope of the line? pls help I need the answer

Drupady [299]

Answer:

the slope of a horizontal line is 0

6 0

3 years ago