The diameter of a circle is 10 meters. What is the area, in square meters , of the circle
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Cos(<span>θ) < 0, so we know it would be in Quadrant 2 or 3
then csc(</span>θ) = 257, but csc(θ) =
= 257
==> sin(<span>θ) =
it is positive, so now we can determine that is in Quadrant 2
sin(</span>θ) = opp./hyp both of opp and hyp are positive but adj suppose to negative because that way it leads the cos(<span>θ) < 0
</span>cos(<span>θ) = adj/hyp
</span>Pythereom to find the adj:
cosθ =
tanθ =
cos<span>θ = </span>
then csc(</span>θ) = 257, but csc(θ) =
==> sin(<span>θ) =
it is positive, so now we can determine that is in Quadrant 2
sin(</span>θ) = opp./hyp both of opp and hyp are positive but adj suppose to negative because that way it leads the cos(<span>θ) < 0
</span>cos(<span>θ) = adj/hyp
</span>Pythereom to find the adj:
cosθ =
tanθ =
cos<span>θ = </span>
<h2>Equations of Circles</h2>
Generally, you'd see the equation of a circle organized in the following format:
is the center
is the radius
To determine the equation given the center and the radius:
- Plug both pieces of information into the general equation
- Simplify
We're given:
- Radius: 99
- Center: (-1,-8)
Plug the radius and center into the equation as r and (h,k):