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Natasha2012 [34]
3 years ago
12

At a high school championship game 1200 tickets were sold. Student tickets cost $1.50 each and adult tickets cost $5.00 each. Th

e total revenue collected for the game was $3200. How many of each ticket were sold for the game?
Mathematics
1 answer:
max2010maxim [7]3 years ago
4 0

Answer:

Students= 800

Adults= 400

Step-by-step explanation:

Given data

number of tickets= 1200

let students be x

and adults be y

x+y= 1200--------------------1

'

The total revenue collected for the game was $3200

so

1.5x+5y=3200-------------2

Solve 1 and 2 for x and y

x= 1200-y

put this is 2

1.5( 1200-y)+5y=3200-------------2

1800-1.5y+5y= 3200

3.5y= 3200-1800

3.5y=1400

Divide both sides by 3.5

y= 1400/3.5

y=400

Put y= 400 in 1

x+400= 1200

x= 1200-400

x=800

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Answer:

The number of boxes of candy sold are:

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12 large boxes of candy.

Step-by-step explanation:

Let the number of small boxes sold = x

Let the number of large boxes sold = y

we are given the following information:

x + y = 52 - - - - - -(1)   (Chara sold 52 boxes of candy)

3.5(y) + 1.75(x) = 112 - - - - - - (2)   (Chara sold $112 worth of candy)

From the two equations above, x and y can be solved as follows:

x + y = 52   - - - - - -(1)

x = 52 - y    - - - - - - (3)

putting the value if x in equation (3) to replace x in equation (2);

3.5(y) + 1.75(x) = 112 - - - - - - (2)

3.5(y) + 1.75(52 - y) = 112

3.5y + 91 - 1.75y = 112

(3.5y - 1.75y) + 91 = 112

1.75y = 112 - 91 = 21

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y = 12

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x = 52 - y    - - - - - - (3)

x = 52 - 12 = 40

Therefore,

40 small boxes and 12 large boxes of candy were sold.

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Romashka-Z-Leto [24]

Answer:

There are 20 pennies, 33 nickels and 11 quarters

Step-by-step explanation:

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