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2 years ago

9

If Juan drives 24 miles in 3 hours,how many miles does Juan drive in 1 hour

2 answers:

ikadub [295]2 years ago

8 0

Answer:

8 miles

Step-by-step explanation:

24/3 = 8

Bingel [31]2 years ago

6 0

8

Step-by-step explanation:

24 ÷ 3 = 8

m / h = m/h

you divide the distance by the time

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Divide 3 by 8, then multiply z by the result

Sonbull [250]

3÷ 8 ·z

3/8 ·z

3/8z

I think i'm just supposed to simplifiy it??

8 0

3 years ago

Question 2 Multiple Choice Worth 5 points)

DerKrebs [107]

Answer:

√20 units.

Step-by-step explanation:

Please see attached photo for diagram.

The other leg of the triangle is x as shown in the attached photo.

Using the pythagoras theory, we can obtain the the value of x as follow:

x² = 4² + 2²

x² = 16 + 4

x² = 20

Take the square root of both side.

x = √20 units

Therefore, the value of the other leg x of the triangle is √20 units

5 0

3 years ago

Pears cost $0.92 per pound and apples cost $1.10 per pound. Mr. Bonilla bought 3.75 pound of pears and 2.1 pounds of apples. How

Blababa [14]

3.75* .92= $3.45

2.1* 1.10= $2.31

$3.45
+ $2.31
_______
$5.76

6 0

3 years ago

Read 2 more answers

Consider the equation below. f(x) = 2x3 + 3x2 − 336x (a) Find the interval on which f is increasing. (Enter your answer in inter

Vaselesa [24]

We have been given a function $f(x)=2x^3+3x^2-336x$ . We are asked to find the interval on which function is increasing and decreasing.

(a). First of all, we will find the critical points of function by equating derivative with 0.

$f'(x)=2(3)x^{2}+3(2)x^1-336$

$f'(x)=6x^{2}+6x-336$

$6x^{2}+6x-336=0$

$x^{2}+x-56=0$

$x^{2}+8x-7x-56=0$

$(x+8)-7(x+8)=0$

$(x+8)(x-7)=0$

$x=-8,x=7$

So $x=-8,7$ are critical points and these will divide our function in 3 intervals $(-\infty,-8)U(-8,7)U(7,\infty)$ .

Now we will find derivative over each interval as:

$f'(x)=(x+8)(x-7)$

$f'(-9)=(-9+8)(-9-7)=(-1)(-16)=16$

Since $f'(9)>0$ , therefore, function is increasing on interval $(-\infty,-8)$ .

$f'(x)=(x+8)(x-7)$

$f'(1)=(1+8)(1-7)=(9)(-6)=-54$

Since $f'(1)$ , therefore, function is decreasing on interval $(-8,7)$ .

Let us check for the derivative at $x=8$ .

$f'(x)=(x+8)(x-7)$

$f'(8)=(8+8)(8-7)=(16)(1)=16$

Since $f'(8)>0$ , therefore, function is increasing on interval $(7,\infty)$ .

(b) Since $x=-8,7$ are critical points, so these will be either a maximum or minimum.

Let us find values of f(x) on these two points.

$f(-8)=2(-8)^3+3(-8)^2-336(-8)$

$f(-8)=1856$

$f(7)=2(7)^3+3(7)^2-336(7)$

$f(7)=-1519$

Therefore, $(-8,1856)$ is a local maximum and $(7,-1519)$ is a local minimum.

(c) To find inflection points, we need to check where 2nd derivative is equal to 0.

Let us find 2nd derivative.

$f''(x)=6(2)x^{1}+6$

$f''(x)=12x+6$

$12x+6=0$

$12x=-6$

$\frac{12x}{12}=-\frac{6}{12}$

$x=-\frac{1}{2}$

Therefore, $x=-\frac{1}{2}$ is an inflection point of given function.

3 0

3 years ago

If a bus driver leaves her first stop by 7:00 a.m., her route will take less than 37 minutes. If she leaves after 7:00 a.m., she

lianna [129]

Answer:

i dont know lol

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers