You are dealing with pulleys?
can be done with addition of the two equations to eliminate T.
+
=
we can cancel m₁ by dividing both sides by it, assuming mass is not zero
a₂ = 6.125 m/s² ( do significant digits if you need to)
Mass of the car = 1200 kg
Mass of the truck = 2100 kg
Total mass of car and truck = 2100 + 1200 = 3300 kg
Since, the car pushes the truck. Hence, they will move together and will have same acceleration.
Let the acceleration be a.
According to Newton's second law:
F(net) = ma
F = 4500 N
4500 = 3300 × a
a = 1.36 m/s^2
Let the force applied by the car on truck be F.
F = F(net) on the truck
F = ma
F = 2100 × 1.36
F = 2856 N
Hence, the force applied by the car on the truck is 2856 N
A) travel outside the necleus
Answer:
15.106 N
Explanation:
From the given information,
The weight of the bucket can be calculated as:
The mass of the water accumulated in the bucket after 3.20s is:
To determine the weight of the water accumulated in the bucket, we have:
For the speed of the water before hitting the bucket; we have:
v = 8.4 m/s
Now, the force required to stop the water later when it already hit the bucket is:
F = 1.68 N
Finally, the reading scale is:
= 7.154 N + 6.272 N + 1.68 N
= 15.106 N
The correct answer that would best complete the given statement above would be the last option: COLDER. Climates on Earth get colder <span>as you move from the equator to the poles. The places that are located near or on the equator experience the warmest or the hottest climates such as Africa. Hope this answer helps. </span>