The restoring force of the spring cancels the weight of the mass, so by Newton's second law
∑ F = F[spring] - mg = 0 ⇒ F[spring] ≈ 45.1 N
where m = 4.60 kg and g = 9.80 m/s². Then the spring constant is k such that by Hooke's law,
F[spring] = k x
where x = 0.0231 m. Then the spring constant is
k = F[spring]/x ≈ 1950 N/m
1) 25 because I did 5*5
2) It would be the third option because a longer wire has a higher resistance and a thinner wire causes electrons to travel at a slower rate
Not sure about the last one, sorry
Answer:
When net force of zero acting on a ball which is at rest , then the object center of mass will not accelerate , but the object may begin to rotate .
Explanation:
Here when there is an object where several forces are acing upon are zero then the center of mass will not accelerate because we know that

Where
acceleration of center of mass
= net force = 0
So the acceleration of center of mass will be zero
But the torque ,may not be zero as torque is product of individual force and perpendicular force .
Since if torque is not equal to zero then the object may begin to rotate
Answer:
Accurate Measurements
Explanation:
Always put in accurate measurements when arguing