The mass of substance left after 7 days is 13.09 g
The mass of substance left, N is given by
N = N₀exp(-λt) where λ = decay constant and N₀ = initial mass of substance present = 24 g and t = time
Also, λ = 0.693/t' where t' = half-life of iodine = 8 days
So, λ = 0.693/t'
λ = 0.693/8
λ = 0.086625/day
Since the mass of substance left is N = N₀exp(-λt) and we require the mass of substance after t = 7 days,
N = N₀exp(-λt)
N = 24 gexp(-0.086625/day × 7 days)
N = 24 gexp(-0.606375)
N = 24 g × 0.5453
N = 13.09 g
So, the mass of substance left after 7 days is 13.09 g
Learn more about radioactive decay here:
brainly.com/question/23705307
Answer:
6 5/40 + 4 16/40
10. 21/40
Change the denominator into the LCD and change the numerator.
keep the denominator the same and add the numerator
add the whole numbers
If b was equal to zero, then x would be undefined.
Also note:
As the value of b increases, the value of x decreases. And vice versa.
Answer:In this equation, we can start by understanding that "x" has a value of 8, as given in the ordered pair. When multiplied by 5, this leads to "40 - 2y = 30". Next, we can subtract 40 from both sides of the equation. This leads us to a value of "-2y = -10". The next step would be to divide both sides by -2 as a way of isolating "y", which leads us to a final value of "y = 5". The final ordered pair would be (8,5).
Step-by-step explanation:
The relationship of distance-speed-time
distance = velocity × time
d = vt
Given:
v₁ = 35 mph
v₂ = 50 mph
the hypotenuse = 366
for example h is the time in hour
Solution:
d₁² + d₂² = (hypotenuse)²
(v₁t)² + (v₂t)² = 366²
(35h)² + (50h)² = 366²
1,225h² + 2,500h² = 133,956
3,725h² = 133,956
h² = 133,956 / 3,725
h² = 35.9613
h = 5.99
to the nearest hour ⇒ 6
The buses will be 366 miles apart in 6 hours
