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N76 [4]
3 years ago
7

Amelia used 1/7 of an ounce of butter to make 1/4 of a pound of Jello. How many ounces of butter are needed to make 1 pound of J

ello
Mathematics
2 answers:
son4ous [18]3 years ago
3 0

Answer:

4/7

Step-by-step explanation:

Gnesinka [82]3 years ago
3 0

Answer:

4/7 ounces of butter makes a pound of jello

Step-by-step explanation:

7 times 4 is 28, so 4/28 ounces of butter for 7/28 pounds of jello. so 4/28 times 4 is 16/28. 16/28 is our answer, then simplified is 4/7. Thats how we get our answer.

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maw [93]

Answer:76.82 is more

Step-by-step explanation:

5 0
2 years ago
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A ladder 20 feet long is leaning against the wall of a house. The base of the ladder is pulled away from the wall at a rate of 2
alukav5142 [94]

Answer:

0.17 °/s

Step-by-step explanation:

Since the ladder is leaning against the wall and has a length, L and is at a distance, D from the wall. If θ is the angle between the ladder and the wall, then sinθ = D/L.

We differentiate the above expression with respect to time to have

dsinθ/dt = d(D/L)/dt

cosθdθ/dt = (1/L)dD/dt

dθ/dt = (1/Lcosθ)dD/dt where dD/dt = rate at which the ladder is being pulled away from the wall = 2 ft/s and dθ/dt = rate at which angle between wall and ladder is increasing.

We now find dθ/dt when D = 16 ft, dD/dt = + 2 ft/s, and L = 20 ft

We know from trigonometric ratios, sin²θ + cos²θ = 1. So, cosθ = √(1 - sin²θ) = √[1 - (D/L)²]

dθ/dt = (1/Lcosθ)dD/dt

dθ/dt = (1/L√[1 - (D/L)²])dD/dt

dθ/dt = (1/√[L² - D²])dD/dt

Substituting the values of the variables, we have

dθ/dt = (1/√[20² - 16²]) 2 ft/s

dθ/dt = (1/√[400 - 256]) 2 ft/s

dθ/dt = (1/√144) 2 ft/s

dθ/dt = (1/12) 2 ft/s

dθ/dt = 1/6 °/s

dθ/dt = 0.17 °/s

8 0
3 years ago
WILL MARK BRAINLEIST ​
yaroslaw [1]

Answer:

Which one do we have to answer?

Step-by-step explanation:

First of all, I can't even see the whole question. Second of all, you didn't tell us what to answer. Please comment on this answer on which question you need help with.

8 0
3 years ago
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30 = y - 2<br> and work plzzz
9966 [12]

Answer:

Step-by-step explanation:

y - 2 = 30

y = 32

3 0
2 years ago
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The symphonic choir and the jazz choir are recording songs for an album. The album can be no more than 72
Brut [27]

Answer:

The maximum number of songs that the symphonic choir can record is 14

Step-by-step explanation:

Let

x ----> the number of songs of the symphonic choir

we know that

The number of songs of the jazz choir multiplied by its average time per song plus the the number of songs of the symphonic choir multiplied by its average time per song, must be less than or equal to 72 minutes

so

The inequality that represent this situation is

3(7)+3.5(x)\leq 72

solve for x

21+3.5x\leq 72

subtract 21 both sides

3.5x\leq 51

divide by 3.6 both sides

x\leq 14.6\ songs

therefore

The maximum number of songs that the symphonic choir can record is 14

3 0
2 years ago
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