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maria [59]
1 year ago
6

ANSWER QUICKLY!!! What is an advantage of digital portfolios?

Computers and Technology
1 answer:
algol131 year ago
8 0
Easy to carry or utilize
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What are your undertale + au ships?
fenix001 [56]
What is an undertale? Lol
3 0
3 years ago
List and explain three ways study groups benefit your learning.
SashulF [63]

Answer:

Studying in groups can have many effective outcomes and be beneficial. Here are some ways studying in a group is benefical,

1.  More support, limits chances of procrastination

<u>      With many people, everyone is assigned a role or there is more determination by all peoples to get the work done than an individual being the only one responsible than many trying to accomplish the completion of the project. </u>

2. More people means more parts can get done effectively and taking notes is easier.

<u>      More people allow the work (depending on the project of assignment) for the work to get more focused and worked on faster with the designated roles given. </u>

3. More interactive and allows (sometimes an enjoyable times) and to even learn faster than independently.

      People, not all however, might like the company, there's support and even people skills is enhanced by being in the group.

3 0
2 years ago
The remove() method in the Queue interface ________. Group of answer choices retrieves, but does not remove, the head of this qu
salantis [7]
<h2>Question:</h2>

The remove() method in the Queue interface ________.

A. retrieves, but does not remove, the head of this queue, returning null if this queue is empty

B. retrieves and removes the head of this queue, or null if this queue is empty

 

C. retrieves, but does not remove, the head of this queue, throwing an exception if this queue is empty

D. retrieves and removes the head of this queue and throws an exception if this queue is empty

<h2>Answer:</h2>

D. retrieves and removes the head of this queue and throws an exception if this queue is empty

<h2>Explanation:</h2>

In Java, the Queue interface is found in the java.util package and inherits from the Collection interface. It is used to store elements which are processed in the order in which they are inserted. This means that the first element will be processed first.

The Queue interface has many methods. Some of them are;

i. add(): allows elements to be added to the queue.

ii. remove(): retrieves and removes elements from the head of the queue. The head of the queue points to the first element of the queue. If the queue is empty, the remove() method throws an exception called the <em>NoSuchElementException</em>

<em />

iii. poll(): retrieves and removes the element at the head of the queue. Unlike the remove() method, if the queue is empty, a <em>null </em>is returned.

iv. peek(): retrieves but does not remove the element at the head of the queue. Just like the poll() method, a <em>null</em> is returned if the queue is empty.

7 0
2 years ago
Taking a suitable example in c language explain the of call by value and call by reference concepts.
Degger [83]

Answer: The difference between call by value and call by reference is that in call by value the actual parameters are passed into the function as arguments whereas in call by reference the address of the variables are sent as parameters.

Explanation:

Some examples are:

call by value

#include <stdio.h>  

void swap(int, int);

int main()

{  int a = 10, b= 20;

 swap(a, b);

 printf("a: %d, b: %d\n", a, b);

}  

void swap(int c, int d)

{

 int t;

 t = c; c = d; d = t;

}  

OUTPUT

a: 10, b: 20

The value of a and b remain unchanged as the values are local

//call by reference

#include <stdio.h>

 void swap(int*, int*);

 int main()

{

 int a = 10, b = 20;

 swap(&a, &b);   //passing the address

 printf("a: %d, b: %d\n", a, b);

}

void swap(int *c, int *d)

{

 int t;

 t = *c; *c = *d; *d = t;

}

OUTPUT

a: 20, b: 10

due to dereferencing by the pointer the value  can be changed which is call by reference

8 0
3 years ago
Help to how to write pseudo code to insert a new node to Binary Search Tree. Using C++.
dimulka [17.4K]

Answer:

Let the function be Node* ins(Node *root,int k)

if root node is NULL then return new node with data equal to k.

If the k <root->data

root->left=ins(root->left,k);

else if k >root->data

root->right =ins(root->right,k);

At last return root.

Explanation:

Node is always inserted at the at the leaf node.We will search k in the tree if we hit a the leaf node the new node is inserted as the child of the leaf node.

4 0
2 years ago
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