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kap26 [50]
2 years ago
13

Graph the system of inequalities to show all possible solutions. {y<3x-2 {y ≥ -x+3

Mathematics
2 answers:
antiseptic1488 [7]2 years ago
6 0

Answer:

Step-by-step explanation:

The solution is a darkest area of a plane. All dots inside this area are the solutions of the system.

Semmy [17]2 years ago
5 0

Answer:

see attachment for graph

Step-by-step explanation:

< or > : dashed line

≤ or ≥ : solid line

< or ≤ : shade below the line

> or ≥ : shade above the line

<u>To graph the line y < 3x-2</u>

Rewrite the equation as: y = 3x - 2

Find two points on the line:

when x = 0,  y = 3(0) - 2 = -2  →  (0, -2)

when x = 3,  y = 3(3) - 2 = 7  →  (3, 7)

Plots the found points (0, -2) and (3, 7).

Draw a straight, dashed line through the points.

<u>To graph the line y ≥ -x + 3</u>

Rewrite the equation as: y = -x + 3

Find two points on the line:

when x = 0,  y = -(0) + 3 = 3  →  (0, 3)

when x = 3,  y = -(3) + 3 = 0  →  (3, 0)

Plots the found points (0, 3) and (3, 0).

Draw a straight, solid line through the points.

Shade above the solid line and below the dashed line to the right of where the two lines intersect.  <u>The shaded area is the area of all possible solutions</u>.

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The weight of a car is modeled with the polynomial x2 + 10x + 200. The weight of a x3 + x + 100. Which polynomial represents the
Zolol [24]
<h3>The combined weight of a car and truck is given as the polynomial   P(W) = x³ + x² + 11 x + 300</h3>

Step-by-step explanation:

The weight of the car is given as:

P(C)  =  x² + 10 x  + 200

The weight of the truck is given as:

P(T)  =  x³ +  x  + 100

Now, the combined weight of both vehicles is given as

= Weight of Car P(C)   + Weight of Truck P(T)

P(W)  = x² + 10 x  + 200 +  x³ +  x  + 100

         =  x³ + x² + (10 x +  x)+ (200 + 100)

         = x³ + x² + 11 x + 300

⇒ The combined weight of a car and truck is given as the polynomial P(W) = x³ + x² + 11 x + 300

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=y%20%3D%20%20-%20x%20%2B%2010%20%5C%5C%20y%20%3D%20x%20%2B%202" id="TexFormula1" title="y = -
Zepler [3.9K]
The two ys must be the same. Equate the two right hand sides.

-x + 10 = x + 2 add x to both sides.
10 = x + x + 2
10 = 2x + 2 Subtract 2 from both sides.
8 = 2x Divide by 2
x = 8/2
x = 4

Now solve for y
y = x + 2
y = 4 + 2
y = 6

Use the other equation to check it.

y = - x + 10
y = -4 + 10
y = 6
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