Yes because the median and range are not a function of the totality of the sample set, the median is just value that is halfway of the set and the range is the difference of the highest and lowest value. As long as the lowest and highest value and the halfway value are the same in each set, the median and range will be equal no matter what the other values of the set are.
Step-by-step explanation:
I believe the answer is A and B
Answer:
Yes and the answer is 16/5
Step-by-step explanation:
Find the reciprocal of the divisor
Reciprocal of 1/6 : 6/1
Now, multiply it with the dividend
8/15 ÷ 1/6 = 8/15 × 6/1
And after that you get 48/15 but after reducing the fraction, the answer is 16/5. ( In mixed form, 3 1/5 )
I hope this helps and I am a middle school student answering this question.
In order to subtract mixed fractions, we must convert them into improper fractions first. To do this simply multiply the whole number by the denominator and add the numerator. The product of this operation will be the new numerator (the whole number is no longer present).
(56 + 7)/8 - (12 + 1)/4
= 63/8 - 13/4
Now that we have our fractions in improper form, we must find the least common denominator which is 8. To avoid changing the value of the second fraction, multiply both the numerator and denominator by 2 (which is essentially 2/2 which equals to 1).
63/8 - 26/8
= 37/8
