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UNO [17]
3 years ago
5

A store is having a 15% sale on movies. A movie is on sale for 22.10, what is the original price of the movie?

Mathematics
1 answer:
baherus [9]3 years ago
4 0
The answer is $25.415
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Henry is making a corn grits recipe that calls for 1/4 cup of corn grits for every 1/2 cup of water. How much water will he need
Archy [21]

Method 1:

\begin{array}{ccc}\dfrac{1}{4}\ \text{cup of corn}&-&\dfrac{1}{2}\ \text{cup of water}\\\\1\dfrac{1}{2}=\dfrac{3}{2}\ \text{cup of corn}&-&x\ \text{cup of water}\end{array}\qquad\text{cross multiply}\\\\\\\dfrac{1}{4}\cdot x=\dfrac{3}{2}\cdot\dfrac{1}{2}\\\\\dfrac{1}{4}x=\dfrac{3}{4}\qquad\text{multiply both sides by 4}\\\\\boxed{x=3}

<h3>Answer: Henry will need 3 cups of water.</h3>

Method 2:

\begin{matrix}\dfrac{1}{4}\ \text{cup of corn}&-&\dfrac{1}{2}\ \text{cup of water}&|\text{multiply both sides by 2}\\\\\dfrac{1}{2}\ \text{cup of corn}&-&1\ \text{cup of water}&|\text{multiply both sides by 2}\\\\1\ \text{cup of corn}&-&2\ \text{cup of water}&|\end{matrix}

\begin{matrix}\left(\dfrac{1}{2}+1\right)\ \text{cups of corn}&-&(1+2)\ \text{cups of water}\\\\1\dfrac{1}{2}\ \text{cups of corn}&-&3\ \text{cups of water}\end{matrix}

<h3>Answer: Henry will need 3 cups of water.</h3>
5 0
3 years ago
Read 2 more answers
Let f(x)=100−10+e−0.1x .
lianna [129]
What are you solving for?
If you are solving for × then I hope this helps

Let's solve for x.

f(x)= 100−10+e−0.1x

Step 1: Add 0.1x to both sides.

xf+0.1x=−0.1x+e+90+0.1x

xf+0.1x = e+90

Step 2: Factor out variable x.

x(f+0.1) = e+90

Step 3: Divide both sides by f+0.1.

x(f+0.1)/ f+0.1 =e+90/ f+0.1

x=e+90/ f+0.1

Answer:

x= e+90/ f+0.1
4 0
3 years ago
Read 2 more answers
ppositional angle closure in eyes with narrow angles: comparison between the fellow eyes of acute angle-closure glaucoma and nor
skad [1K]

Here is the comparision

Purpose:To compare the topologic features of acute primary angle-closure glaucoma eyes before an attack to those of normotensive eyes, assuming that untreated fellow acute primary angle-closure glaucoma eyes are candidates for an acute attack.

Methods:Under dark-room conditions, ultrasound biomicroscopy was used to examine 50 eyes (12 fellow eyes of acute primary angle-closure glaucoma and 38 normotensive cases with a closure-possible narrow angle). Before any surgical or laser intervention, all eyes were examined and found to have normal pupillary response without the use of any topical drugs. Each eye was examined at four predetermined angle locations. The chamber angle configuration parameters were measured and compared between the two groups.

Result:Appositional angle closures were detected in 27 fellow eyes and 48 normotensive eyes with a closure-possible narrow angle. The incidence differed statistically between the two groups (69.2% in fellow eyes and 48% in normotensive eyes). In the fellow eye group, appositional angle closures beginning at the angle's entrance were more frequently detected. The distance between the iris root and the bottom of the angle varied significantly between groups.

Conclusion:Acute primary angle-closure glaucoma fellow eyes have different topologic features than normotensive narrow-angled eyes, as well as a higher incidence of appositional closure, which may predispose these eyes to an impending acute attack.

Learn more about glaucoma here:

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8 0
1 year ago
What are the coordinates of A'and B'when AB is reflected in the y-axis? Show your work or explain
vaieri [72.5K]

The coordinates of A'and B'when AB is reflected in the y-axis are; (-2,5) and (-6,3).

<h3>What are the coordinates of A'and B'when AB is reflected in the y-axis?</h3>

According to the task content, it follows that the reflected points A' and B's coordinates are required.

From the graph, the coordinates of A= (2,5) and B= (6,3).

On this note, the coordinates of A' and B' upon reflection over the y-axis is; (-2,5) and (-6,3) respectively.

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7 0
2 years ago
What is the result of isolating y^2 in the equation below (x-2)^2+y^2=64?
natta225 [31]

What is the result of isolating y^2 in the equation below (x-2)^2+y^2=64?

Solution:

We want to isolate y^{2} from the equation (x-2)^{2} +y^{2} =64

To isolate y^{2}, we must try to get y^{2} alone

So, We must subtract (x-2)^{2} from both sides

(x-2)^{2}-(x-2)^{2}  +y^{2} =64-(x-2)^{2}

0 +y^{2} =64-(x-2)^{2}

y^{2} =64-(x^{2}-4x+4)

Distributing '-' inside parenthesis

y^{2} =64-x^{2} +4x -4

y^{2} =60-x^{2} +4x

6 0
3 years ago
Read 2 more answers
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