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3 years ago

Can two dot plots have the same median and range but not have completely different shapes?

1 answer:

3 0

Yes because the median and range are not a function of the totality of the sample set, the median is just value that is halfway of the set and the range is the difference of the highest and lowest value. As long as the lowest and highest value and the halfway value are the same in each set, the median and range will be equal no matter what the other values of the set are.

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PLEASE DO NUMBER 5 PLZ I REALLY NEED HELP NO BOTS NO BS

ivann1987 [24]

Answer:

a. -x, y b. x, y c. x, -y

Step-by-step explanation:

hope this helps:)

3 0

3 years ago

JL is a diameter of circle k. If tangents to circle I are constructed through points L and K what relationships would exist betw

luda_lava [24]

i. Let t be the line tangent at point J. We know that a tangent line at a point on a circle, is perpendicular to the diameter comprising that certain point. So t is perpendicular to JL
let l be the tangent line through L. Then l is perpendicular to JL ii. So t and l are 2 different lines, both perpendicular to line JL.
2 lines perpendicular to a third line, are parallel to each other, so the tangents t and l are parallel to each other.
Remark. Draw a picture to check the

3 0

3 years ago

Jai Narayan sells two radio sets for 2288 each.

san4es73 [151]

Answer:

Step-by-step explanation:

S.P of each radio=$ 2288

Total S.P= $2\times 2288=$ $4576

Gain=10%

Lose=10%

C.P= $\frac{S.P\times 100}{100+gain(in\;percent)}$

C.P= $\frac{S.P\times 100}{100-loss(in\;percent)}$

By using the formula

C.P of one radio= $\frac{2288\times 100}{110}=$ $2080

C.P of another radio= $\frac{2288\times 100}{100-10}$ =$2542.2

Total C.P of two radios=2080+2542.2=$4622.2

Total C.P >Total S.P

Loss=S.P-C.P

Loss=4622.2-4576=$46.2

Loss%= $\frac{Loss}{C.P}\times 100$

Loss %= $\frac{46.2}{4622.2}\times 100=$ 1%

Hence, his loss 1%

5 0

3 years ago

Use diagrams or the description of equivalent ratios to show thay 2:3,4:6, and 8:12 are equivalent

VikaD [51]

So
lets say we have
a/b=2a/2b
we know that if we invert one and multiply it by the other (divide them), we get 1 because a/a=1 where a=a

so
2/3 and 4/6 are equivelent because if you divide them we get 12/12=1

2/3 and 8/12 are equivilent because if you divide them we get 24/24=1

and sinde 2/3=4/6 and 2/3=8/12, 2/3=4/6=8/12

they are equivlent

6 0

3 years ago

Leila puts an integer into the "In" box of each machine.

kykrilka [37]

The machines represent equivalent expressions.

The output produced by both machines is 372

The equation represented on machine A is:

$\mathbf{y = 2(5x + 3) - 24}$