If f(x)=6x+2,
f(x+3)=6(x+3)+2
f(x+3)=6x+18+2
f(x+3)=6x+20
Answer:
x^2 -2xy -10y^2
x^2 -9xy +4 y^2
3x^3 +6x^2 -24 x +27
Step-by-step explanation:
3x^2-5xy -6y^2 -( 2x^2 -3xy+4y^2)
= 3x^2- 2x^2 -5xy +3xy-6y^2 -4 Y^2
= x^2 -2xy -10y^2
2x^2−5xy+y^2 -( x^2+4xy−3y^2)
=2 x^2 -x^2 -5xy -4xy +y^2 +3 y^2
=x^2 -9xy +4 y^2
7x^3−16x+18- (4x^3−6x^2+8x−9)
= 7x^3 -4x^3 + 6x^2-16x- 8x +18 +9
=3x^3 +6x^2 -24 x +27
4 × 104
+6 × 103
+6 × 102
+5 × 101
+6 × 100<span>
</span>
Answer:
Step-by-step explanation:
A(-5,-2),B(-2,-2), C(-5,2)
find distance first:d=√(x2-x1)^2+(y^2-y1^2)
AB: 3
BC: 5
AC: 4
perimeter of triangle=3+5+4=12
compliment angle=90
90+34=124
5x+17+x+19=180
x=24
Answer:
you solve what is inside the parenthesis first to get rid of it, then its almost like you got rid of it.
