Answer:
64, 16/25, .64 --- 12.5, 1/8, 0.125 --- 140, 1 2/5, 1.4 --- 275, 2 3/4, 2.75 --- 8, 2/25, 0.08
Step-by-step explanation:
Hope you get this in time! :D
1. the least common multiple of 9 and 12.
9 18 27 36
12 24 36
36
2. GCF of 9 and 12
1 3 9
1 2 3 4 6 12
3
Answer:
Heights of 29.5 and below could be a problem.
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches.
This means that 
There may be a problem when a child is in the top or bottom 5% of heights. Determine the heights of 2-year-old children that could be a problem.
Heights at the 5th percentile and below. The 5th percentile is X when Z has a p-value of 0.05, so X when Z = -1.645. Thus


Heights of 29.5 and below could be a problem.
K.E=0.5mv^2
GPE=mgh
The child has both K.E and GPE


g is taken as 9.81