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exis [7]
3 years ago
12

If u do 3 I’ll mark Brainlynest u don’t have to do 3 it depends but also 14 points

Mathematics
1 answer:
Helen [10]3 years ago
4 0

Answer:

Step-by-step explanation:

A(-5,-2),B(-2,-2), C(-5,2)

find distance first:d=√(x2-x1)^2+(y^2-y1^2)

AB: 3

BC: 5

AC: 4

perimeter of triangle=3+5+4=12

compliment angle=90

90+34=124

5x+17+x+19=180

x=24

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Please help quickly!!!!!
Wewaii [24]

Answer:

64, 16/25, .64   ---   12.5, 1/8, 0.125    ---    140, 1 2/5, 1.4    ---    275, 2 3/4, 2.75    ---    8, 2/25, 0.08

Step-by-step explanation:

Hope you get this in time! :D

6 0
3 years ago
A total of 684 tickets were sold for the school play. They were either adult tickets or student tickets. There were 66 fewer stu
dlinn [17]
375

Mark brainliest please
6 0
2 years ago
Read 2 more answers
1. What is the least common multiple of both 9 and 12?
Kisachek [45]
1. the least common multiple of 9 and 12.
  9 18 27 36
  12 24 36
  36
2. GCF of 9 and 12
  1 3 9
  1 2 3 4 6 12
  3
7 0
3 years ago
8.52 The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches
sweet [91]

Answer:

Heights of 29.5 and below could be a problem.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches.

This means that \mu = 32, \sigma = 1.5

There may be a problem when a child is in the top or bottom 5% of heights. Determine the heights of 2-year-old children that could be a problem.

Heights at the 5th percentile and below. The 5th percentile is X when Z has a p-value of 0.05, so X when Z = -1.645. Thus

Z = \frac{X - \mu}{\sigma}

-1.645 = \frac{X - 32}{1.5}

X - 32 = -1.645*1.5

X = 29.5

Heights of 29.5 and below could be a problem.

4 0
2 years ago
60 pOINTS HELP PLEASE 4. A 20-kg child is tossed up into the air by her parent. The child is 2 meters off the ground traveling 5
Solnce55 [7]
K.E=0.5mv^2
GPE=mgh
The child has both K.E and GPE
ke = 0.5 \times 20 \times  {5}^{2}  \\ ke = 10 \times 25 \\ ke = 250 \: joules
gpe = 20 \times 9.81 \times 2 \\ gpe = 40 \times 9.81 \\ gpe = 392.4 \: joules
g is taken as 9.81
6 0
3 years ago
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