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s344n2d4d5 [400]
1 year ago
9

Solve each triangle: Find all the missing sides and angles. Round answers to the nearest tenth.

Mathematics
1 answer:
horrorfan [7]1 year ago
3 0

Step-by-step explanation:

let \: angle \: be \:  \alpha  \\  \tan( \alpha )  =  \frac{p}{b}  \\  \tan(69.9)  = \frac{9.7}{bc}  \\ bc =  \frac{9.7}{2.73}  \\ bc = 3.55 \\ by \: using \: pythagorean \: theorem \\ ab =  \sqrt{ {9.7}^{2} }  +  {2.73}^{2}  \\ ab = 10.07

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The hypotenuse of a right triangle measures 18 cm and one of its legs measures 12 cm. Find the measure of the other leg. If nece
Serggg [28]

Answer:

16 cm

Step-by-step explanation:

A right triangle, with the hypotenuse = 18, one side = 7, and the other side = x.

Since this is a right triangle, use the pythagorean theorem to find the value for x.

let a = 7 for one side, and let c = 18 for the hypotenuse. And, let c = x for the other side.

The pythagorean theorem is: c^2 = a^2 + b^2.

18^2 = 7^2 + x^2324 = 49 +x^2

x^2 = 324 - 49 = 275So, x = sqrt(275) = 16.5 cm

3 0
2 years ago
Read 2 more answers
Change 2x-y=-4 into slope-intercept form with steps
Art [367]

Answer:

Y=2x+4

Step-by-step explanation:

2x-y=-4

subtract 2x

-y=-2x-4

divide by -1

y=2x+4

3 0
3 years ago
Solve the triangles below
nataly862011 [7]
I guess you want the missing angle.
The missing angle is 83

4 0
3 years ago
For a boat to float in a tidal bay, the water must be at least 2.5 meters deep. The depth of water around the boat, ????(????),
Effectus [21]

Answer:

a. Period, T = 12.57 hours. b. Latest time = 294.16 hours, 6 a.m 12 days later

Step-by-step explanation:

For a boat to float in a tidal bay, the water must be at least 2.5 meters deep. The depth of water around the boat, d(t), in meters, where t is measured in hours since midnight, is d(t) = 5 + 4.6sin(0.5t). (a) What is the period of the tides in hours? (b) If the boat leaves the bay at midday, what is the latest time it can return before the water becomes too shallow?

a. The period, T of the tides is gotten from ω = 2π/T, where ω is the angular frequency of the wave and T its period. Comparing the sine part of equation of the tides with the general equqtion of a sine wave, Asinωt, thus Asinωt = 4.6sin(0.5t),

so ω = 0.5 rad/s.

Equating this to 2π/T implies

0.5 = 2π/T

therefore, T = 2π/0.5 = 12.566 hours ≈ 12.57 hours

b. The tide becomes too low if it is less than 2.5 m i.e d(t) < 2.5 m. So, equating d(t) as 2.5 in the tidal equation, we have d(t) = 5 + 4.6sin(0.5t).

2.5< 5+ 4.6sin(0.5t)

2.5-5 < 4.6sin(0.5t)

-2.5 < 4.6sin(0.5t)

-2.5/4.6 < sin(0.5t)

-0.543 < sin(0.5t)

sin⁻¹(-0.543)<0.5t

-32.92<0.5t. Since we cannot have negative time, we add 180 to -32.92 to give 147.08

147.08<0.5t

t>147.08/0.5=294.16 hours

So, if t is greater than 294.16 hours, the water will be shallow. That is, below 2.5 m. which is 12 days 6hours 8 min 38 s which is 6 a.m 12 days later

3 0
3 years ago
Identify the slope and y-intercept of y=4 over 5x plus 1.
KiRa [710]
The slope is 4/5 and the y-intercept is when x=0, So y=(0)+1, y-intercept is 1
7 0
3 years ago
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