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3 years ago

13

What else would need to be congruent to show that abc is congruent to xyz by sas

1 answer:

QveST [7]3 years ago

3 0

AC=XZ is the answer.

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Save me the headache

maxonik [38]

$(9\sin2x+9\cos2x)^2=81$

Taking the square root of both sides gives two possible cases,

$9\sin2x+9\cos2x=9\implies\sin2x+\cos2x=1$

or

$9\sin2x+9\cos2x=-9\implies\sin2x+\cos2x=-1$

Recall that

$\sin(\alpha\pm\beta)=\sin\alpha\cos\beta\pm\cos\alpha\sin\beta$

If $\alpha=2x$ and $\beta=\dfrac\pi4$ , we have

$\sin\left(2x+\dfrac\pi4\right)=\dfrac{\sin2x+\cos2x}{\sqrt2}$

so in the equations above, we can write

$\sin2x+\cos2x=\sqrt2\sin\left(2x+\dfrac\pi4\right)=\pm1$

Then in the first case,

$\sqrt2\sin\left(2x+\dfrac\pi4\right)=1\implies\sin\left(2x+\dfrac\pi4\right)=\dfrac1{\sqrt2}$

$\implies2x+\dfrac\pi4=\dfrac\pi4+2n\pi\text{ or }\dfrac{3\pi}4+2n\pi$

(where $n$ is any integer)

$\implies2x=2n\pi\text{ or }\dfrac\pi2+2n\pi$

$\implies x=n\pi\text{ or }\dfrac\pi4+n\pi$

and in the second,

$\sqrt2\sin\left(2x+\dfrac\pi4\right)=-1\implies\sin\left(2x+\dfrac\pi4\right)=-\dfrac1{\sqrt2}$

$\implies2x+\dfrac\pi4=-\dfrac\pi4+2n\pi\text{ or }-\dfrac{3\pi}4+2n\pi$

$\implies2x=-\dfrac\pi2+2n\pi\text{ or }-\pi+2n\pi$

$\implies x=-\dfrac\pi4+n\pi\text{ or }-\dfrac\pi2+n\pi$

Then the solutions that fall in the interval $[0,2\pi)$ are

$x=0,\dfrac\pi4,\dfrac\pi2,\dfrac{3\pi}4,\pi,\dfrac{5\pi}4,\dfrac{3\pi}2,\dfrac{7\pi}4$

5 0

3 years ago

Read 2 more answers

What comes next!T,F,S,S,M

Wittaler [7]

Answer:

E,D

Step-by-step explanation:

6 0

3 years ago

The first 5 terms of a sequence are shown below:

nirvana33 [79]

Step-by-step explanation:

To find the formula for the nth term ,

First , find the common difference or common ratio.

Common difference =

$T_2-T_1 \\ - 2 - 3 \\ = - 5$

Common ratio =

$T_2/T_1 \\ \frac{ - 2}{3}$

The common difference applies to the other given numbers for example :

$T_3- T_2 = - 7 - ( - 2) \\ = - 7 + 2 = - 5$

this proves that it is an arithmetic sequence and the given formula for the nth term of an arithmetic sequence is

T_n =a(n-1)d

Where n = no of terms

a= first term

d= common difference

6 0

3 years ago

A group of cat owners was asked about the number of cats each owns. The results are shown in the frequency table. Number of Freq

Yakvenalex [24]

Answer:

Cats Owned B. 2 3

Hope I helped! :)

8 0

3 years ago

If each of the following questions were asked to a group of second graders, which question would NOT be a statistical question?

sweet-ann [11.9K]

Answer:

d

Step-by-step explanation:

just makes sense bc they're all in 2nd grade

8 0

3 years ago