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Neporo4naja [7]
2 years ago
9

Ramon uses models to compare two decimial he says 0.09 greater than 0.1 because 9>1 which of these explain ramon's mistake

Mathematics
1 answer:
Shalnov [3]2 years ago
5 0

Answer:

Ramon's mistake was that he used whole numbers in comparison to decimals, which is not an accurate way to solve. Think about it this way, 0.1 is the tens place, 0.01 is the hundreds place. Which would be greater 100% of the time? The hundreds place, in decimal terms, the hundredths.

0.09 is greater than 0.1

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Answer:

y = 7.50 + 1.50x

Step-by-step explanation:

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4 0
3 years ago
14-5+20÷2^2+4 wich order
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14-5+20÷2∧2+4

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3 years ago
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In the equation

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divide both sides by 2^x to get

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Alternatively, you can divide both sides by 3^x:

\dfrac{3^x}{3^x} = \dfrac{3\cdot 2^x}{3^x} \\\\ \implies 1 = 3 \cdot\left(\dfrac23\right)^x \\\\ \implies \left(\dfrac23\right)^x = \dfrac13

Then take the base-2/3 logarith of both sides to get

\log_{2/3}\left(2/3\right)^x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x \log_{2/3}\left(\dfrac23\right) = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(3^{-1}\right) \\\\ \implies \boxed{x = -\log_{2/3}(3)}

(Both answers are equivalent)

8 0
3 years ago
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