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OLEGan [10]
2 years ago
15

There are 240 calories in 5 ounces of a type of ice cream. How many calories are in 8 ounces of that ice cream?

Mathematics
2 answers:
s344n2d4d5 [400]2 years ago
7 0
There 330 calories in 8 ounces
madam [21]2 years ago
3 0

Answer:

384 calories in 8 ounces of that ice cream

Step-by-step explanation:

240/5= 48

1 ounze  of ice cream has 48 calories

48x8=  384

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Help me out the number inside the triangle is really throwing me off tbh
prisoha [69]

We are given an angle of 60° and a side of 15 cm.

We are given the opposite and is looking for the hypotenuse so we will use the sine ratio to find x.

sin = opp/hyp

hyp = 15 / sin 60

hyp = 17.32...

//

We can also use the tangent ratio to find the adjecent and then use pythagorean to find x.

tan = opp/adj

adj = 15 / tan 60

adj = 8.660.....

8.660....² + 15² = 300²

since the square root of 300 is an irrational number, we have to turn it into a mixed radical.

The answer would be the top one.

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3 years ago
Hey randomperson can you send the last comment you sent on the last question i asked?
maw [93]

Um thanks for the free points but ok .-.

4 0
3 years ago
Read 2 more answers
The answer is 48 can someone explain how?
mestny [16]

Answer:

<h2>48</h2>

Step-by-step explanation:

(1)

apple × apple × 2apple = 54

2apple³ = 54    <em>divide both sides by 2</em>

apple³ = 27 → apple = ∛27

apple = 3

(2)

apple + apple × green_apple = 24   <em>substituite apple = 3</em>

3 + 3 × green_apple = 24        <em>subtract 3 from both sides</em>

3 × green_apple = 21         <em>divide both sides by 3</em>

green_apple = 7

(3)

strawberry - bannana - banana = 0 → strawberry = 2banana

(4)

strawberry + banana + cherry = 24     <em>substitute from (3)</em>

2banana + banana + cherry = 24

3banana + cherry = 24

(5)

apple + banana - cherry = -1          <em>substitute apple = 3</em>

3 + banana - cherry = -1         <em>subtr3 from both sides</em>

banana - cherry = -4

Add both sides of (4) and (5)

 3banana + cherry = 24

<u>+banana - cherry = -4       </u>

4banana = 20       <em>divide both sides by 4</em>

banana = 5

Substitute it to (4):

3(5) + cherry = 24

15 + cherry = 24      <em>subtract 15 from both sides</em>

cherry = 9

Substitute to the last equation:

3 + 5 × 9 = 3 + 45 = 48

/USED PEMDAS/

7 0
3 years ago
patrick had 1\6 package of cookies he split it with his two how much of the package did each brother get
mihalych1998 [28]

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Use the Fundamental Theorem of Calculus to find the "area under curve" of
lozanna [386]

Answer:

\displaystyle A = 300

General Formulas and Concepts:

<u>Calculus</u>

Integrals

  • Definite Integrals
  • Area under the curve
  • Integration Constant C

Integration Rule [Reverse Power Rule]:                                                                   \displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C

Integration Rule [Fundamental Theorem of Calculus 1]:                                        \displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)

Integration Property [Multiplied Constant]:                                                             \displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx

Integration Property [Addition/Subtraction]:                                                           \displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx

Area of a Region Formula:                                                                                       \displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

f(x) = 6x + 19

Interval [12, 15]

<u>Step 2: Find Area</u>

  1. Substitute in variables [Area of a Region Formula]:                                       \displaystyle A = \int\limits^{15}_{12} {(6x + 19)} \, dx
  2. [Integral] Rewrite [Integration Property - Addition/Subtraction]:                   \displaystyle A = \int\limits^{15}_{12} {6x} \, dx + \int\limits^{15}_{12} {19} \, dx
  3. [Integrals] Rewrite [Integration Property - Multiplied Constant]:                   \displaystyle A = 6\int\limits^{15}_{12} {x} \, dx + 19\int\limits^{15}_{12} {} \, dx
  4. [Integrals] Integrate [Integration Rule - Reverse Power Rule]:                      \displaystyle A = 6(\frac{x^2}{2}) \bigg| \limits^{15}_{12} + 19(x) \bigg| \limits^{15}_{12}
  5. Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]:              \displaystyle A = 6(\frac{81}{2}) + 19(3)
  6. Simplify:                                                                                                             \displaystyle A = 300

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

Book: College Calculus 10e

7 0
3 years ago
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