10) A rhombus has a
diagonal 8.6 mm long
and an area of 81.7 mm. what is the
perimeter?
1 answer:
Answer:
P=41.72
Step-by-step explanation:
S=ACxDB/2
81.7=8.6xDB/2
81.7=4.3xDB|:4.3
19(mm)=DB
DO=19/2=9.5
OC=8.6/2=4.3
(O is the center of the rhombus, where two diagonals meet)
a²+b²=c² (DO²+OC²=DC²)
9.5²+4.3²=c²
90.25+18,49=c²
√108,74=√c²
c≈10.43
P=4c
P=4x10.43
P=41.72
Hope it helps:)
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